【发布时间】:2019-10-11 14:27:42
【问题描述】:
我是 Rails 新手。所以不知道如何遵循DRY方法。让我们深入探讨这个问题。
如果我遵循相同的代码,我的控制器中有两种方法。那么如何减少我的代码。在这两种方法中,只有模型名称有所不同。请帮助我
我需要这样的东西
array = ['Userservice', 'Userschedule' ]
array.each do |el|
draft_info = el.find_by(user_id: 39, save_option: "publish")
draft_info.delete if !draft_info.nil?
@user_info = el.find_by(user_id: 39, save_option: "draft")
el.create(@user_info.attributes.merge({:save_option => "publish", :id => el.maximum(:id).to_i.next }))
end
def create_publish_user
publish_user_schedule
publish_user_service
end
def publish_user_service
draft_service = Userservice.where(user_id: current_user.id, save_option: "publish").delete_all
user_service = Userservice.where(user_id: current_user.id, save_option: "draft")
user_service.each { |ser|
Userservice.create(ser.attributes.merge({:save_option => "publish", :id => Userservice.maximum(:id).to_i.next }))
}
end
def publish_user_schedule
draft_schedule = Userschedule.where(user_id: current_user.id, save_option: "publish").delete_all
user_schedule = Userschedule.where(user_id: current_user.id, save_option: "draft")
user_schedule.each { |sch|
Userschedule.create(sch.attributes.merge({:save_option => "publish", :id => Userschedule.maximum(:id).to_i.next }))
}
end
【问题讨论】:
标签: ruby-on-rails ruby ruby-on-rails-6