使用 HTTParty gem 时如何设置我的 `base_uri`？

Question

我正在创建一个使用外部地理位置 API 的小型 Rails。它应该接受一个字符串（地址）并返回坐标。我不确定如何使用 HTTParty gem 设置基本 URI。 API 的文档说可以将请求发送到端点

GET https://eu1.locationiq.com/v1/search.php?key=YOUR_PRIVATE_TOKEN&q=SEARCH_STRING&format=json

如何在我的类方法中设置令牌和搜索字符串？这是我到目前为止的代码。

locationiq_api.rb

  include HTTParty
  base_uri "https://eu1.locationiq.com/v1/search.php?key=pk.29313e52bff0240b650bb0573332121e&q=SEARCH_STRING&format=json"

  attr_accessor :street

  def find_coordinates(street)
    self.class.get("/locations", query: { q: street })
  end

  def handle_error
    if find_coordinates.code.to_i = 200
      find_coordinates.parsed_response
    else
      raise "Couldn't connect to LocationIQ Api"
    end
  end
end```

locations controller:

```class LocationsController < ApplicationController
before_action :find_location, only: [:show, :destroy, :edit, :update]

def new
  @search = []
  # returns an array of hashes
  @search = locationiq_api.new.find_coordinates(params[:q])['results'] unless params[:q].nil?
end

def create
  @location = Location.new(location_params)
  if @location.save
    redirect_to root_path
  else
    render 'new'      
  end
end

private

  def location_params
    params.require(:location).permit(:place_name, :coordinate)
  end

  def find_location
    @location = Location.find(params[:id])
  end
end```

Answer 1

这样的事情可能会有所帮助：

class LocationIqApi
  include HTTParty
  base_uri "https://eu1.locationiq.com/v1/search.php"

  def initialize(api_key, format = "json")
    @options = { key: api_key, format: format }
  end

  def find_coordinates(street)
    self.class.get("/locations", query: @options.merge({ q: street }))
  end

  def handle_error
    if find_coordinates.code.to_i = 200
      find_coordinates.parsed_response
    else
      raise "Couldn't connect to LocationIQ Api"
    end
  end
end

然后，当您想使用它时，您需要使用您的密钥创建一个新实例：

@search = LocationIqApi.new(YOUR_API_KEY_HERE).find_coordinates(params[:q])