【问题标题】:JSON to a JSON array Cannot deserialize the current JSON objectJSON 到 JSON 数组无法反序列化当前 JSON 对象
【发布时间】:2013-10-05 22:05:06
【问题描述】:

我正在使用Json.Net 将Object Json 数据反序列化为对象/集合(列表)

我不确定自己做错了什么,我已经尝试过:

List<LanguageObject> lang = JsonConvert.DeserializeObject<List<LanguageObject>>(jsonData);

并尝试过:

LanguageObject.Results lang = JsonConvert.DeserializeObject<LanguageObject.Results>(jsonData);

我收到此错误:

Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[LanguageObject]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly.   
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object.
Path 'meta', line 1, position 8.

这是我的 Json:

{"meta":
{
    "status":200,
    "message":[],
    "resultSet":
          {"id":"05"},
    "pagination":     
     {
        "count":2,
        "pageNum":1,
        "pageSize":2,
        "totalPages":1,
        "sort":"ordinal",
        "order":"Asc",
        "currentUri":null,
        "nextUri":null
      }
    },
    "results":   
     {
         "id":0,
         "name":
         "Language",
         "DName":null,
         "qvalue":"language",
         "language":null,
         "mUsageCount":null,
         "Ordinal":0,
      "items":
         [
           {
             "id":0,
             "name":"English",
             "DName":"English",
             "qvalue":null,
             "language":null,
             "mUsageCount":null,
             "Ordinal":0,
             "items":[]
           },
           {
             "id":0,
              "name":"Spanish",
              "DName":"Spanish;",
              "qvalue":null,
              "language":null,
              "mUsageCount":null,
              "Ordinal":0,"
              items":[]
           }
         ]
     }}

LanguageObject.cs

   Public class LanguageObject
    {
    public class ResultSet
    {
        public string id { get; set; }
    }

    public class Pagination
    {
        public int count { get; set; }
        public int pageNum { get; set; }
        public int pageSize { get; set; }
        public int totalPages { get; set; }
        public string sort { get; set; }
        public string order { get; set; }
        public object currentUri { get; set; }
        public object nextUri { get; set; }
    }

    public class Meta
    {
        public int status { get; set; }
        public List<object> message { get; set; }
        public ResultSet resultSet { get; set; }
        public Pagination pagination { get; set; }
    }

    public class Item
    {
        public int id { get; set; }
        public string name { get; set; }
        public string DName { get; set; }
        public object qvalue { get; set; }
        public object language { get; set; }
        public object mUsageCount { get; set; }
        public int Ordinal { get; set; }
        public List<object> items { get; set; }
        public List<object> __invalid_name__
                      items { get; set; }
    }

    public class Results
    {
        public int id { get; set; }
        public string name { get; set; }
        public object DName { get; set; }
        public string qvalue { get; set; }
        public object language { get; set; }
        public object mUsageCount { get; set; }
        public int Ordinal { get; set; }
        public List<Item> items { get; set; }
    }

    public class RootObject
    {
        public Meta meta { get; set; }
        public Results results { get; set; }
    }

}

【问题讨论】:

    标签: json json.net json-deserialization


    【解决方案1】:

    我没有看到您的问题中定义了 LanguageObject 类。但是,我确实看到了 RootObject 课程。根据您发布的内容,您需要像这样反序列化:

    RootObject root = JsonConvert.DeserializeObject<RootObject>(jsonData);
    

    然后你可以从RootObject获取Results

    Results lang = root.Results;
    

    【讨论】:

    • LanguageObject.cs 是我的课程我已经更新了我的问题,但是我会试一试并发布我的结果。
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