JSON数组到数组列表使用c#

Question

我正在尝试将 JSON 转换为列表，请任何人帮助我。

public class User
{
    public String id { get; set; }
    public String imageURL { get; set; }
    public String search { get; set; }
    public String status { get; set; }
    public String username { get; set; }
}



List<User> users = JsonConvert.DeserializeObject<List<User>>(resp.Body);

JSON
{
    "KfWE8S9jWJdWnAZEbOtHTtisNwO2":
        {"id":"KfWE8S9jWJdWnAZEbOtHTtisNwO2"
        ,"imageURL":"https://firebasestorage.googleapis.com/v0/b/bchat-af5e5.appspot.com/o/uploads%2F1542785437375.jpg?alt=media&token=be1ce806-fecf-4081-9dad-f0a20e5d8489"
        ,"search":"rene vizconde"
        ,"status":"online"
        ,"username":"Rene Vizconde"},
    "ScpDnyQCyKemXSgdo3jEvZFNxY83":
        {"id":"ScpDnyQCyKemXSgdo3jEvZFNxY83"
        ,"imageURL":"default"
        ,"search":"yeli potpot"
        ,"status":"offline"
        ,"username":"Yeli Potpot"},
    "cnPYOdHYWaaLDQmchELLvw85DBf1":
        {"id":"cnPYOdHYWaaLDQmchELLvw85DBf1"
        ,"imageURL":"https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcSHilM1ke9pZePBJTobMTcktggiw-UywdqAIpf-VX9nqecKl6b4wQ"
        ,"search":"bards disc"
        ,"status":"offline"
        ,"username":"Bards Disc"},
    "tWTbllTxaVM9WQnsNwnBgc3ixLM2":
        {"id":"tWTbllTxaVM9WQnsNwnBgc3ixLM2"
        ,"imageURL":"default"
        ,"search":"renz angelo"
        ,"status":"offline"
        ,"username":"Renz Angelo"}
    }

Answer 1

您可以简单地将您的 json 反序列化为 Dictionary<string, User> 而不是 List<User>。

class Program
{
    static void Main(string[] args)
    {
        var data = JsonConvert.DeserializeObject<Dictionary<string, User>>(resp.Body);

        foreach (var item in data)
        {
            User user = item.Value;

            Console.WriteLine("id: " + user.id);
            Console.WriteLine("imageURL: " + user.imageURL);
            Console.WriteLine("search: " + user.search);
            Console.WriteLine("status: " + user.status);
            Console.WriteLine("username: " + user.username);
            Console.WriteLine();
        }

        Console.ReadLine();
    }
}

输出：

Answer 2

您的 JSON 有问题。尽管它的结构“在语法上”是正确的，但它的设计却很糟糕。

您使用 ID 命名 JSON 的成员，然后在这些成员的每个对象中引用该 ID。

不要重复自己。

由于成员的名称是动态的，因此您不能使用该根对象来反序列化 JSON。 （这不是 List<User>，该 JSON 中没有列表，而是对象）

考虑使用这种结构而不是（注意括号来创建对象数组）

[
    {
        "id":"KfWE8S9jWJdWnAZEbOtHTtisNwO2"
        ,"imageURL":"https://firebasestorage.googleapis.com/v0/b/bchat-af5e5.appspot.com/o/uploads%2F1542785437375.jpg?alt=media&token=be1ce806-fecf-4081-9dad-f0a20e5d8489"
        ,"search":"rene vizconde"
        ,"status":"online"
        ,"username":"Rene Vizconde"
    },
    {
        "id":"ScpDnyQCyKemXSgdo3jEvZFNxY83"
        ,"imageURL":"default"
        ,"search":"yeli potpot"
        ,"status":"offline"
        ,"username":"Yeli Potpot"
    },
    {
        "id":"cnPYOdHYWaaLDQmchELLvw85DBf1"
        ,"imageURL":"https://encrypted-tbn0.gstatic.com/images?q=tbn:ANd9GcSHilM1ke9pZePBJTobMTcktggiw-UywdqAIpf-VX9nqecKl6b4wQ"
        ,"search":"bards disc"
        ,"status":"offline"
        ,"username":"Bards Disc"
    },
    {
        "id":"tWTbllTxaVM9WQnsNwnBgc3ixLM2"
        ,"imageURL":"default"
        ,"search":"renz angelo"
        ,"status":"offline"
        ,"username":"Renz Angelo"
    }
]