【发布时间】:2016-07-30 06:15:13
【问题描述】:
我想使用 Foundation 的 JSONSerialization.data(withJSONObject obj: AnyObject, options opt: WritingOptions = []) throws -> Data 。但是,我无法弄清楚如何将我的值类型转换为适合该方法的引用类型。
例如,尝试序列化一个简单的 String 数组会失败,因为该方法需要引用类型,而不是值类型:
root@1c6c66df21cf:/tmp# swift
Welcome to Swift version 3.0 (swift-3.0-PREVIEW-3). Type :help for assistance.
1> import Foundation
2> JSONSerialization.data( withJSONObject: [String]() )
error: repl.swift:2:48: error: argument type '[String]' does not conform to expected type 'AnyObject'
JSONSerialization.data( withJSONObject: [String]() )
铸造不起作用:
root@1c6c66df21cf:/tmp# swift
Welcome to Swift version 3.0 (swift-3.0-PREVIEW-3). Type :help for assistance.
1> import Foundation
2> let value = [String]()
value: [String] = 0 values
3> let reference = value as! NSArray
reference: Foundation.NSArray = <extracting data from value failed>
Execution interrupted. Enter code to recover and continue.
Enter LLDB commands to investigate (type :help for assistance.)
我还尝试按照该版本核心 Foundation 的 unit tests 中的示例:
root@1c6c66df21cf:/tmp# swift
Welcome to Swift version 3.0 (swift-3.0-PREVIEW-3). Type :help for assistance.
1> import Foundation
2> let value = [String]()
value: [String] = 0 values
3> let reference = value.bridge()
reference: Foundation.NSArray = <extracting data from value failed>
error: Couldn't lookup symbols:
(extension in Foundation):Swift.Array.bridge () -> Foundation.NSArray
系统信息供参考:
root@1c6c66df21cf:/tmp# uname -a
Linux 1c6c66df21cf 4.4.12-boot2docker #1 SMP Wed Jun 1 22:45:59 UTC 2016 x86_64 x86_64 x86_64 GNU/Linux
root@1c6c66df21cf:/tmp# swift --version
Swift version 3.0 (swift-3.0-PREVIEW-3)
Target: x86_64-unknown-linux-gnu
【问题讨论】: