Hapi - 如何将有效负载解析为 JSON？

Question

所以我正在尝试同时研究 HTTP/TCP/IP 协议、Nodejs、MongoJS 和 MongoDB。所以我试图用 Hapi Web 框架来解决一些问题。我可以使用我的 iOS 模拟器与服务器通信，但是我似乎无法正确解析有效负载。我知道我可以使用 URL 中的参数来发送信息，但我想使用有效负载。

所以我最终将它保存到 Mongo 中。

(
    {
    "_id" = 5431f161bb859872034d2456;
    "{\"userLastNameKey\":\"Kwon\",\"userEmailKey\":\"email\",\"userFirstNameKey\":\"Michael\",\"userUsernameKey\":\"username\",\"userPasswordKey\":\"password\"}" = "";
},
    {
    "_id" = 5431fe5694ed4721046c1f8c;
    "{\"userLastNameKey\":\"Kwon2\",\"userEmailKey\":\"email2\",\"userFirstNameKey\":\"Michael2\",\"userUsernameKey\":\"username2\",\"userPasswordKey\":\"password2\"}" = "";

这是我的通话代码。

    // This will add a new user to the database
function addUser(request, response){

    db.usersCollection.save(request.payload, function (err, saved){
        if(err || !saved)
        {
            console.log("User not saved");
        } else 
          {
              console.log("User saved");
          }
    });
}

我想尝试让它变成这样的最终结果

    (
    {
    "_id" = 5431f161bb859872034d2456,
    "userLastNameKey" = "Kwon", 
    "userEmailKey" = "email",
    "userFirstNameKey"= "Michael",
    "userUsernameKey" = "username",
    "userPasswordKey" = "password",
    }
)

这是 iOS 代码

   NSDictionary *userData = [User userToDictionary: newUserInfo];
   NSData *userJSON = [NSJSONSerialization dataWithJSONObject: userData options: 0 error: nil]; 

 NSURL *url = [NSURL URLWithString: urlString];
 NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL: url];
 [request setHTTPMethod: @"POST"];
 [request addValue: @"application/json" forHTTPHeaderField: @"Content-Type"];

    // This will set up the url session
    NSURLSessionConfiguration* config = [NSURLSessionConfiguration defaultSessionConfiguration];
    NSURLSession *session = [NSURLSession sessionWithConfiguration: config];

    NSURLSessionUploadTask *uploadTask = [session uploadTaskWithRequest: request fromData: userJSON completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {

            if(error)
            {

            } else
              {

              }

          }];

          [uploadTask resume];
      }

有谁知道我是怎么做到的？

Answer 1

{
  "_id" = 5431f161bb859872034d2456;
  "userLastNameKey" = "Kwon"; 
  "userEmailKey" = "email";
  "userFirstNameKey"= "Michael";
  "userUsernameKey" = "username";
  "userPasswordKey" = "password";
}

那是不是 JSON 对象。您需要使用逗号而不是分号。和冒号而不是等号。您的 ID 也不是十进制数字，因此最好将其设为字符串。

你的对象看起来像：

{
  "_id" : "5431f161bb859872034d2456",
  "userLastNameKey" : "Kwon",
  "userEmailKey" : "email",
  "userFirstNameKey" : "Michael",
  "userUsernameKey" : "username",
  "userPasswordKey" : "password"
}

要解析（格式良好的）JSON 字符串，请使用：var JSONObject = JSON.parse(JSONstring);