如何从以下 JSON 中删除“isCustom”键值对

Question

例如，我收到来自邮递员的 JSON 响应并将其存储在变量中。如何从此响应中删除特定键？

{"editdata":[{"A11":"T55","ID":"4","FVAModifiedDateLongValues":"3:1334835002030","ModifiedDateLongValue":1614614214967,"F033":[{"名称":"p3","Type":"String","Values":null,"Description":"p3","isCustom":false},{"Name":"p3","Type":"String ","Values":null,"Description":"p3","isCustom":false}],"flag":"edit"]}

Answer 1

您可以使用要删除的对象迭代数组，然后使用 delete operator 从每个对象中删除字段。

let myObject = {
    "editdata": [{
        "A11": "T55",
        "ID": "4",
        "FVAModifiedDateLongValues": "3:1334835002030",
        "ModifiedDateLongValue": 1614614214967,
        "F033": [{
          "Name": "p3",
          "Type": "String",
          "Values": null,
          "Description": "p3",
          "isCustom": false
        }, {
          "Name": "p3",
          "Type": "String",
          "Values": null,
          "Description": "p3",
          "isCustom": false
        }],
        "flag": "edit"}]
    };
// if you want to delete it for all objects in the editdata array, you could do a nested forEach.
myObject.editdata[0].F033.forEach(obj => delete obj.isCustom);
console.log(myObject);