如何检索没有任何属性名称的 JSON 数组？

Question

我通常不熟悉使用 API 和 JSON。到目前为止，我已经做了几个练习，但偶然发现了这个 JSON 文件：Link 并且不知道如何检索它。这是我的 API 代码。GetCategories 任务是有问题的。感谢任何花时间阅读本文并帮助我的人。

using System;
using System.Collections.Generic;
using System.Net.Http;
using System.Threading.Tasks;
using Newtonsoft.Json;


namespace ChuckNorris.API
{


public class ChuckClient
    {

    public async Task<ChuckNorrisJoke> GetARandomChuckNorrisJoke()
    {
        string url = $"https://api.chucknorris.io/jokes/random";
        HttpClient client = new HttpClient();
        var response = await client.GetStringAsync(url);
        return JsonConvert.DeserializeObject<ChuckNorrisJoke>(response);
    }


    public async Task<ChuckNorrisJoke> GetARandomChuckNorrisJokeFromCategory(string category)
    {
        string url = $"https://api.chucknorris.io/jokes/random?category={category}";
        HttpClient client = new HttpClient();
        var response = await client.GetStringAsync(url);
        return JsonConvert.DeserializeObject<ChuckNorrisJoke>(response);
    }


    public async Task<List<ChuckNorrisJoke>> GetCategories()
    {
        string url = $"https://api.chucknorris.io/jokes/categories";
        HttpClient client = new HttpClient();
        var response = await client.GetStringAsync(url);
        return JsonConvert.DeserializeObject<List<ChuckNorrisJoke>>(response);
    }


    public async Task<ChuckNorrisJoke> GetFreeTextSearchJoke(string query)
    {
        string url = $"https://api.chucknorris.io/jokes/search?query={query}";
        HttpClient client = new HttpClient();
        var response = await client.GetStringAsync(url);
        return JsonConvert.DeserializeObject<ChuckNorrisJoke>(response);
    }
}

public class ChuckNorrisJoke
{
    [JsonProperty("Categories")]
    public string[] Categories { get; set; }
    [JsonProperty("Value")]
    public string Value { get; set; }
    [JsonProperty("Total")]
    public int Total { get; set; }
    [JsonProperty("Result")]
    public ChuckNorrisJoke[] Result { get; set; }
    
}


}

Answer 1

就像@Jimi 说的那样。只需要将响应反序列化为列表即可。