使用 JOLT 转换重命名嵌套数组中的字段

Question

我想使用 JOLT 转换库重命名嵌套在另一个数组中的数组中的字段。 1.要重命名的字段是数组中的顶级字段 2.要重命名的两个字段在一个嵌套数组中

我尝试使用通配符，但它们没有给我预期的输出。我使用的是 JOLT 0.0.22 版本。

输入 JSON：

{
    "country": "usa",
    "state": [
        {
            "stateName": "TX",
            "location": "south",
            "cities": [
                {
                    "name": "Austin",
                    "pop": "1M"
                },
                {
                    "name": "Dallas",
                    "pop": "2M"
                }
            ]
        },
        {
            "stateName": "CA",
            "location": "west",
            "cities": [
                {
                    "name": "SanFran",
                    "pop": "3M"
                },
                {
                    "name": "LosAngeles",
                    "pop": "4M"
                }
            ]
        }
    ]
}

预期输出：

{
    "country": "usa",
    "state": [
        {
            "stateName": "TX",
            "locatedIn": "south",  // name change here
            "cities": [
                {
                    "cityname": "Austin",  // name change here
                    "citypopulation": "1M" // name change here
                },
                {
                    "cityname": "Dallas",
                    "citypopulation": "2M"
                }
            ]
        },
        {
            "stateName": "CA",
            "locatedIn": "west",
            "cities": [
                {
                    "cityname": "SanFran",
                    "pop": "3M"
                },
                {
                    "cityname": "LosAngeles",
                    "citypopulation": "4M"
                }
            ]
        }
    ]
}

Answer 1

规格

[
  {
    "operation": "shift",
    "spec": {
      "country": "country",
      "state": {
        "*": { // state array index
          "stateName": "state[&1].stateName",
          "location":  "state[&1].location",
          "cities": {
            "*": { // city array index
              "name": "state[&3].cities[&1].cityname",
              "pop":  "state[&3].cities[&1].citypopualtion"
            }
          }
        }
      }
    }
  }
]

Answer 2

为了比较，这是JSLT中的解决方案。

{
  "state" : [for (.state) . | {
    "locatedIn" : .location,
    "cities" : [for (.cities) {
      "cityname" : .name,
      "citypopulation" : .pop
    }],
    * : .
  }],
  * : .
}