集成 Swagger 和以前工作的代码中断：无法从 Object 值反序列化（没有基于委托或属性的 Creator

Question

我成功地将 swagger 集成到了几个 Spring Boot 服务中。
必须通过添加扩展 WebSecurityConfigurerAdapter 的相应 @EnableWebSecurity 类来允许端点绕过身份验证（这对其他服务很好）：

 
 @Configuration
@EnableWebSecurity
@EnableGlobalMethodSecurity(prePostEnabled = true)
@Order(1)
public class AppSecurityConfig extends WebSecurityConfigurerAdapter {

...

@Override
    protected void configure(HttpSecurity httpSecurity) throws Exception {
        httpSecurity
                .antMatcher("/**")
       
       ...
                .antMatchers("/actuator/**").permitAll()
                .antMatchers("/v2/api-docs", "/configuration/**", "/webjars/**","/swagger*/**") // ADDED THIS for swagger 
                .permitAll()  // ADDED THIS for swagger 
                .antMatchers("/challenge").permitAll()
                .antMatchers("/token").permitAll()  // ENDPOINT with complaint now, that was previously ok.
               .anyRequest()
                .authenticated()
                .and()
                .cors();
    }
    ...
    }

然而，对于一个特定的，一旦我添加了相关的招摇代码和依赖项，它似乎已经损坏并抱怨最初的工作原理。

这是投诉的终点：

@PostMapping("/token")
    public ResponseDto token(@Valid @RequestBody TokenRequest request) {
        try {
            return service.generateJwtFromCode(request.getId(), request.getCode());
        }
        ...
        catch (Exception exception) {..
        }
        }

没有找到此类的构造函数：

@AllArgsConstructor
public class TokenRequest {

    @NotEmpty
    @JsonProperty
    private final String id;

    @NotEmpty
    @Getter
    private final String code;

    public UUID getId() {
        return UUID.fromString(id);
    }
  

}

Could not resolve parameter [0] in responseDTO  Controller.token(Service.TokenRequest): Type definition error: [simple type, class TokenRequest]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `service.TokenRequest` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
 at [Source: (PushbackInputStream); line: 1, column: 2]
 o.s.web.servlet.DispatcherServlet        : Failed to complete request: org.springframework.http.converter.HttpMessageConversionException: Type definition error: [simple type, class service.TokenRequest]; nested exception is com.fasterxml.jackson.databind.exc.InvalidDefinitionException: Cannot construct instance of `service.TokenRequest` (no Creators, like default construct, exist): cannot deserialize from Object value (no delegate- or property-based Creator)
 at [Source: (PushbackInputStream); line: 1, column: 2]
o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in …

不确定它与大摇大摆的集成有什么关系。如果我删除 swagger 集成代码，它可以使用相同的代码正常工作，并且不会抱怨类型转换失败。

为了解决这个问题，我也采纳了某人的建议
升级 com.fasterxml.jackson.core 的依赖项 并重建代码。但还是没有成功。

  compileOnly 'com.fasterxml.jackson.core:jackson-databind:2.11.2'

我尝试过但没有解决的问题：

1. 添加了默认/空构造函数 （对于大多数其他有类似问题的人来说，它的工作原理是这样的，对我来说，它会在之后抱怨

error: variable id might not have been initialized
    }

1. 将此添加到 tokenRequest 类中：

@Value
@AllArgsConstructor(onConstructor = @__(@JsonCreator(mode = JsonCreator.Mode.PROPERTIES))

有一个不同的错误：

c.j.MappingJackson2HttpMessageConverter : Failed to evaluate Jackson deserialization for type [[simple type, class TokenRequest]]
InvalidDefinitionException: Invalid type definition for type `TokenRequest`: More than one argument (#0 and #1) left as delegating for Creator [constructor for TokenRequest, annotations: {interface com.fasterxml.jackson.annotation.JsonCreator=@com.fasterxml.jackson.annotation.JsonCreator(mode=DELEGATING)}]: only one allowed
    at com.fasterxml.jackson.databind.exc.InvalidDefinitionException.from(InvalidDefinitionException.java:62)...

Answer 1

解决方案是添加一个默认构造函数并删除最终变量。

@AllArgsConstructor
public class TokenRequest {

    @NotEmpty
    @JsonProperty
    private String id;  // code fixed issue

    @NotEmpty
    @Getter
    private String code;  // code fixed issue

    public TokenRequest(){}  // code fixed issue
    
    public UUID getId() {
        return UUID.fromString(id);
    }
  


}