从目标 C Cocoa 向 php 发送变量

Question

我正在尝试将变量传递给 php 页面，但它没有传递给页面或保存在数据库中。请参阅以下代码中的 cmets：

NSString *fname=@"fname";
NSString *lname=@"lname";
NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objective%20c%20/send.php?first_name=%@&last_name=%@",fname,lname];

NSLog(urlString);

NSURL *url = [ NSURL URLWithString:urlString];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
NSAlert *dq= [[NSAlert alloc] init];
[dq setMessageText:urlString];
[dq runModal];
[request setHTTPMethod:@"GET"];

NSURLConnection* connection = [[NSURLConnection alloc] initWithRequest:request delegate:self];
[connection start];

NSAlert *d= [[NSAlert alloc] init];
[d setMessageText:@"connection"];
[d runModal];

//This is the part I don't understand.
//This line has a problem:  
NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objectivec/send.php?first_name=%@&last_name=%@",fname,lname];

//But when I replace it with
NSString *urlString = @"http://localhost:8888/Test-objectivec/send.php?first_name=My&last_name=nme";

//Then it works just fine.

另外，谁能告诉我如何查看服务器的响应？

Answer 1

NSString *fname=@"fname";
NSString *lname=@"lname";
NSString *urlString = [[NSString alloc]  

NSString *urlString = [[NSString alloc]initWithFormat:@"http://localhost:8888/Test-objectivec/send.php?first_name=%@&last_name=%@",fnamelname];

• 从转换 %20 的“测试目标 c”中删除空格，这会造成问题。

Answer 2

当您创建具有格式的字符串时，您需要注意格式中的特殊字符。特别是在您的情况下%。格式应为：

NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objective%%20c%%20/send.php?first_name=%@&last_name=%@",fname,lname];