Android 应用程序解析 json 数据

Question

你好，我有这个代码我想把这个数据解析为对象现在我得到一个任意类型的字符串

我想分别获取描述对象纬度对象和经度对象

@SuppressLint("NewApi") 
public class MainActivity extends Activity {
private static final String SOAP_ACTION = "http://tempuri.org/xxxx/xxxx";
private static final String METHOD_NAME = "xxxxxx";
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL = "http://10.0.2.2:52564/xxxx.svc/soap";    

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
    StrictMode.setThreadPolicy(policy); 

    TextView textView = new TextView(this);

    setContentView(textView);

    SoapObject request = new SoapObject(NAMESPACE,METHOD_NAME);

    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
    envelope.dotNet = true;
    envelope.setOutputSoapObject(request);
    HttpTransportSE httpTransport = new HttpTransportSE(URL);

    try
    {
        httpTransport.call(SOAP_ACTION, envelope);  
        Object result = (Object)envelope.getResponse();
        textView.setText(result.toString());
    }
    catch (Exception exception)
    {
        textView.setText(exception.toString());
    }
}
}

Answer 1

将 json 解析为对象的最简单方法是使用对象映射器

    ObjectMapper om = new ObjectMapper();
    YourClass object = om.readValue(jsonText, YourClass.class); 

这个对象映射器来自杰克逊：

http://fasterxml.github.io/jackson-databind/javadoc/2.0.0/com/fasterxml/jackson/databind/ObjectMapper.html

Answer 2

您可以只使用 json 对象来处理响应。

以下是代码摘录：

JSONObject obj = new JSONObject(envelope.getResponse().toString());
String Latitude = obj.getString("Latitude");
String Longitude = obj.getString("Longitude");

如果你的 json 看起来像这样：

{
  Latitude: "1.00",
  Longitude: "1.00"
}

根据您的评论，您的 json 如下所示：

[
  {
    "Description": "1",
    "Latitude": 0.369,
    "Longitude": 1.258
  },
  {
    "Description": "2",
    "Lati‌​tude": 1.369,
    "Longitude": 3.258
  },
  {
    "Description": "3",
    "Latitude": 2.369,
    "Longitude": 2.258
  }
]

你可以像这样提取值：

JSONArray obj = new JSONArray(envelope.getResponse().toString());
String[][] values = new String[obj.length()][3];
for(int i = 0; i < obj.length(); i++)
{
    values[i][0] = obj.getJSONObject(i).getString("Description");
    values[i][1] = obj.getJSONObject(i).getString("Latitude");
    values[i][2] = obj.getJSONObject(i).getString("Longitude");
}

这里可能有错误，我只是在这里快速写下。
但这是您需要了解的概念。

Answer 3

因为你的 json 数据是

[
    {
        "Description": "1",
        "Latitude": 0.369,
        "Longitude": 1.258
    },
    {
        "Description": "2",
        "Latitude": 1.369,
        "Longitude": 3.258
    },
    {
        "Description": "3",
        "Latitude": 2.369,
        "Longitude": 2.258
    }
]

为数据创建一个类，如下所示

public class Detail {
    String description;
    Double lat;
    Double longi;

    public Detail(String description, Double lat, Double longi) {
        this.description=description;
        this.lat=lat;
        this.longi=longi;
    }
}

在它为Deatail创建一个arraylist之后，如下所示

List<Detail> detailList=new ArrayList<Detail>();

然后执行以下操作

String jsondata = loadJSONFromAsset();//load data and assign as json string
        JSONArray primaryArray;
        try {
            primaryArray = new JSONArray(jsondata);

            for (int i = 0; i < primaryArray.length(); i++) {

                JSONObject jObject = primaryArray.getJSONObject(i);
                String description = (String) jObject.getString("Description");
                Log.d("Description", description);
                Double latitude =  jObject.getDouble("Latitude");
                Log.d("Latitude", latitude+"");
                Double longitude = jObject.getDouble("Longitude");
                Log.d("Longitude", longitude+"");

                detailList.add(new Detail(description, latitude, longitude));
            }
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

现在您可以从 arraylist 中获取所有详细数据