在 JQ 中使用复杂条件拆分“/”

Question

我有 json：

    "spec": {
        "background": true,
        "failurePolicy": "Fail",
        "rules": [
            {
                "exclude": {
                    "resources": {}
                },
                "generate": {
                    "clone": {}
                },
                "match": {
                    "resources": {
                        "kinds": [
                            "networking.k8s.io/v1/NetworkPolicy"
                        ]
                    }
                },
                "mutate": {},
                "name": "validate-nodeport",
                "validate": {
                    "message": "Services of type NodePort are not allowed.",
                    "pattern": {
                        "spec": {
                            "type": "!NodePort"
                        }
                    }
                }
            }
        ],
        "validationFailureAction": "audit"
    },
    "status": {
        "ready": true
    }
}

我需要解析这个字符串"networking.k8s.io/v1/NetworkPolicy"，但它可能看起来像Kind 或Version/Kind 或Version/Group/Kind。我的 jq 命令仅适用于 Kind 案例：.spec.rules[0].match.resources.kinds[] as $kind

我需要更通用的命令来将字符串拆分为“/”，但在某些情况下可能有一个“/”，在某些情况下可能有两个。我需要正确解析它并编写带有条件的命令

Answer 1

您可以使用/ 运算符和分隔符（在您的情况下为"/"）将字符串拆分为数组：

.spec.rules[0].match.resources.kinds / "/"

[
  "networking.k8s.io",
  "v1",
  "NetworkPolicy"
]

然后，根据元素的存在重新排列：

... | [select(.[1])[0] // null, select(.[2])[1] // null, last]

最后，一次将数组元素分配给多个变量：

... as [$version,$group,$kind]

综合：

(.spec.rules[0].match.resources.kinds / "/")
| [select(.[1])[0] // null, select(.[2])[1] // null, last]
  as [$version,$group,$kind]
| {$version,$group,$kind}

Demo