【发布时间】:2018-01-30 14:01:39
【问题描述】:
使用我的电子表格,我将 2 个 Google 表单绑定到 2 张工作表上。当表单被提交时,脚本执行并完成它的事情。但是,我只希望脚本基于来自单个工作表的提交来执行。就像现在一样,脚本会在任一表单提交时执行。
我的两张纸是: 作业提交 并提交订单
有什么建议吗?
// Work Order
// Get template from Google Docs and name it
var docTemplate = ""; // *** replace with your template ID ***
var docName = "Work Order";
var printerId = "";
function addDates() {
var date = new Date(); // your form date
var holiday = ["09/04/2017","10/09/2017","11/23/2017","12/24/2017","12/25/2017","01/01/2018"]; //Define holiday dates in MM/dd/yyyy
var days = 5; //No of days you want to add
date.setDate(date.getDate());
var counter = 0;
if(days > 0 ){
while (counter < days) {
date.setDate(date.getDate() + 1 );
var check = date.getDay();
var holidayCheck = holiday.indexOf(Utilities.formatDate(date, "EDT", "MM/dd/yyyy"));
if (check != 0 && check != 6 && holidayCheck == -1) {
counter++;
}
}
}
Logger.log(date) //for this example will give 08/16/2017
return date;
}
function createNewDoc(values) {
//Get information from form and set as variables
var email_address = "";
var job_name = values[1];
var order_count = values[2];
var order_form = values[7];
var print_services = values[3];
var priority = values[5];
var notes = values[6];
var formattedDate = Utilities.formatDate(new Date(), "EDT", "MM/dd/yyyy");
var expirationDate = Utilities.formatDate(addDates(), "EDT", "MM/dd/yyyy");
// Get document template, copy it as a new temp doc, and save the Doc's id
var copyId = DriveApp.getFileById(docTemplate)
.makeCopy(docName+' for '+job_name)
.getId();
// Open the temporary document
var copyDoc = DocumentApp.openById(copyId);
// Get the document's body section
var copyBody = copyDoc.getActiveSection();
// Replace place holder keys,in our google doc template
copyBody.replaceText('keyJobName', job_name);
copyBody.replaceText('keyOrderCount', order_count);
copyBody.replaceText('keyOrderForm', order_form);
copyBody.replaceText('keyPrintServices', print_services);
copyBody.replaceText('keyPriority', priority);
copyBody.replaceText('keyNotes', notes);
copyBody.replaceText('keyDate', formattedDate);
copyBody.replaceText('keyDue', expirationDate);
// Save and close the temporary document
copyDoc.saveAndClose();
// Convert temporary document to PDF by using the getAs blob conversion
var pdf = DriveApp.getFileById(copyId).getAs("application/pdf");
// Attach PDF and send the email
var subject = "New Job Submission - " + job_name;
var body = "Here is the work order for " + job_name + ". Job is due " + expirationDate + ".";
MailApp.sendEmail(email_address, subject, body, {htmlBody: body, attachments: pdf});
// Move file to folder
var file = DriveApp.getFileById(copyId);
DriveApp.getFolderById("").addFile(file);
file.getParents().next().removeFile(file);
var newDocName = docName + ' for ' + job_name;
return [copyId, newDocName];
}
function printGoogleDocument(copyId, docName) {
// For notes on ticket options see https://developers.google.com/cloud-print/docs/cdd?hl=en
var ticket = {
version: "1.0",
print: {
color: {
type: "STANDARD_COLOR"
},
duplex: {
type: "NO_DUPLEX"
},
}
};
var payload = {
"printerid" : "",
"content" : copyId,
"title" : docName,
"contentType" : "google.kix", // allows you to print google docs
"ticket" : JSON.stringify(ticket),
};
var response = UrlFetchApp.fetch('https://www.google.com/cloudprint/submit', {
method: "POST",
payload: payload,
headers: {
Authorization: 'Bearer ' + GoogleCloudPrint.getCloudPrintService().getAccessToken()
},
"muteHttpExceptions": true
});
// If successful, should show a job here: https://www.google.com/cloudprint/#jobs
response = JSON.parse(response);
if (response.success) {
Logger.log("%s", response.message);
} else {
Logger.log("Error Code: %s %s", response.errorCode, response.message);
}
return response;
}
// When Form Gets submitted
function onFormSubmit(e) {
var values = e.values;
var returnedDocValues = createNewDoc(values);
var copyId = returnedDocValues[0];
var docName= returnedDocValues[1];
printGoogleDocument(copyId, docName);
}
编辑: 我不确定如何做一个完整或可验证的示例,因为它取决于表单提交。我不经常使用 javascript,所以我还在学习。
无论如何,我更新了我的 onFormSubmit 函数,但是我的其他函数未能执行。该脚本不会创建文档,因此不会发送到谷歌云打印
// When Form Gets submitted
function onFormSubmit(e) {
// Initialize
var rng = e.range;
var sheet = rng.getSheet();
var name = sheet.getName();
// If the response was not submitted to the right sheet, exit.
if(name != "Job Submission") return;
var values = e.values;
var returnedDocValues = createNewDoc(values);
var copyId = returnedDocValues[0];
var docName= returnedDocValues[1];
printGoogleDocument(copyId, docName);
}
【问题讨论】:
-
有没有办法只在特定的工作表上执行脚本?不一定要看表单,只在Sheet1有新表单提交时运行脚本。
-
最好发minimal reproducible example而不是完整代码。
-
不知道如何做一个可验证的代码,因为它依赖于表单,但我已经更新了有问题的函数。
-
您是否将触发失败通知设置为立即发送?您确定表单正在将回复发送到“作业提交”表吗?
-
每天都会发生触发器故障。是的,响应会填充在作业提交表中。
标签: javascript google-apps-script google-sheets google-forms