如何使用谷歌脚本从列表中返回另一个列表中不存在的值

Question

我有两个列表。列表一包含所有当前员工姓名，列表二包含所有当前和过去员工姓名。

我需要开发一个脚本来返回所有过去的名字以及列表二中与他们相关的信息。我编写了这段代码，它将所有当前名称与其当前信息相匹配，但无法弄清楚如何进行反向操作。

function current(){

  var app = SpreadsheetApp;
 
 var activeSheet = app.getActiveSpreadsheet();

  var issued = app.getActiveSpreadsheet().getSheetByName("Issued");

  var waiting = app.getActiveSpreadsheet().getSheetByName("Waiting for Inventory");

  var active = app.getActiveSpreadsheet().getSheetByName("Active Officers");
  
 for (var j = 2; j<100; j++){ 
  
  var officer = issued.getRange(j,11).getValue();
 
  for(var i = 2; i<70; i++){ 

    var officerList = active.getRange(i, 2).getValue();

     if (officer === ""){
       continue; 
      }

     if (officer === officerList){
      var rowInfo = issued.getRange(j,1,1,12).getValues();
      var lastrow = waiting.getLastRow();
      waiting.getRange(lastrow+1,1,1,12).setValues(rowInfo);
      }
    }
  }
}

Answer 1

在数组中检索字符串是否存在的最简单方法是使用indexOf()

• 如果未找到值，它将返回 -1
• 从active 中检索所有官员，并将值转换为1D 数组flat()
• 使用getValues 检索issued 中的所有官员（比使用getValue 的多个请求更有效并循环遍历它们
• 此设置只需要一个 for 循环而不是两个循环，这将使您的代码显着加快

示例：

function current(){
  
  var app = SpreadsheetApp;
  
  var activeSheet = app.getActiveSpreadsheet();
  
  var issued = app.getActiveSpreadsheet().getSheetByName("Issued");
  
  var waiting = app.getActiveSpreadsheet().getSheetByName("Waiting for Inventory");
  
  var active = app.getActiveSpreadsheet().getSheetByName("Active Officers");
  
  var officerList = active.getRange(2, 2, 69, 1).getValues().flat();
  var officers = issued.getRange(2,11,99,1).getValues();
  Logger.log(officerList);
  for (var j = 0; j < 99; j++){     
    var officer = officers[j][0];
    if (officerList.indexOf(officer) ==-1){
      Logger.log("officer " + officer + " from Issued does not exist in Active Officers");
      var rowInfo = issued.getRange(j+2,1,1,12).getValues();
      var lastrow = waiting.getLastRow();
      waiting.getRange(lastrow+1,1,1,12).setValues(rowInfo);
    }
  }
}