如何对数字进行预排序而不搞砸格式？

Question

我正在编写一个自定义函数，它将返回一个数组数组：

function tester(col){
  var rows = [ // this gives me an error on sorting, so turn numbers to strings
    [4,2,3,"Tom"],
    [0,8,9,"Bill"],
    [5,7,1,"Bob"],
    [1,2,3,"Charlie"]
  ];

  rows = [ // turning numbers to strings screws up formatting
    ["4","2","3","Tom"],
    ["0","8","9","Bill"],
    ["5","7","1","Bob"],
    ["1","2","3","Charlie"]
  ];
   rows.sort(function(a, b) {
   return a[col].localeCompare(b[col]); // sort by column passed by user
  });
  return rows;
}

如前所述，如果我传入数字，我会收到错误：

TypeError: Cannot find function localCompare in object

如果我将这些数字转换为可以排序的字符串，但用户无法格式化数字...显示更多小数、逗号、将它们转换为百分比等。我该如何解决这个问题？

编辑：

我尝试了 Buzinas/Kriggs 的建议，但它似乎对数字和否定词进行了词汇排序，而其他排序则不正确。我现在有（注意负数 4 和 750）：

function tester(col){
  var rows = [
    [-4,2,3,"Tom"],
    [0,8,9,"Bill"],
    [5,750,1,"Bob"],
    [1,2,3,"Charlie"]
  ];

  rows.sort(function(a, b) {
     return a[col].toString().localeCompare(b[col].toString());
  });

  return rows;
}

Answer 1

更新

既然你想按数字排序，如果它们是数字，如果它们是字符串，你可以这样做：

function tester(col){
  var rows = [
    [4,2,3,"Tom"],
    [0,8,9,"Bill"],
    [5,7,1,"Bob"],
    [1,2,3,"Charlie"]
  ];

  rows.sort(function(a, b) {
    if (typeof a[col] === 'number')
      return a[col] > b[col];
    return a[col].localeCompare(b[col]);
  });

  return rows;
}