超过最大执行时间，google sheet，如何改进？

Question

大家早上好

我来看你是因为在努力使我的谷歌脚本工作之后，在执行页面上我看到我的脚本工作，但是在我的谷歌工作表上我有一个错误：“超过最大执行时间”。我在互联网上看到自定义 google 脚本函数只留下 30 秒的执行时间，我不知道该怎么做？添加代码来调整此功能？我承认我不明白自定义函数和谷歌应用脚​​本之间的区别，但我知道脚本有 6 分钟的执行时间......这是我的代码摘录：

// Standard functions to call the spreadsheet sheet and activesheet
function GetPipedriveDeals2() {
  let ss = SpreadsheetApp.getActiveSpreadsheet();
  let sheets = ss.getSheets();
  let sheet = ss.getActiveSheet();

   //the way the url is build next step is to iterate between the end because api only allows a fixed number of calls (100) this way i can slowly fill the sheet.
  let url    = "https://laptop.pipedrive.com/v1/products:(id)?start=";
  let limit  = "&limit=500";
  //let filter = "&filter_id=64";
  let pipeline = 1; // put a pipeline id specific to your PipeDrive setup 
  let start  = 1;
  //let end  = start+50;
  let token  = "&api_token=XXXXXXXXXXXXXXXXXXXXXXXX"
  

  let response = UrlFetchApp.fetch(url+start+limit+token); //
  let dataAll = JSON.parse(response.getContentText()); 
  let dataSet = dataAll;
  //let prices = prices;
  //create array where the data should be put
  let rows = [], data;
  for (let i = 0; i < dataSet.data.length; i++) {
  data = dataSet.data[i];
    rows.push([data.id,
               GetPipedriveDeals4(data.id)
               ]);
  }

  Logger.log( 'function2' ,JSON.stringify(rows,null,8) );   // Log transformed data

  return rows;
}

// Standard functions to call the spreadsheet sheet and activesheet
function GetPipedriveDeals4(idNew) {
  let ss = SpreadsheetApp.getActiveSpreadsheet();
  let sheets = ss.getSheets();
  let sheet = ss.getActiveSheet();

   //the way the url is build next step is to iterate between the end because api only allows a fixed number of calls (100) this way i can slowly fill the sheet.
  let url    = "https://laptop.pipedrive.com/v1/products/"+idNew+"/deals:(id,d93b458adf4bf84fefb6dbce477fe77cdf9de675)?start=";
  let limit  = "&limit=500";
  //let filter = "&filter_id=64";
  let pipeline = 1; // put a pipeline id specific to your PipeDrive setup 
  let start  = 1;
  //let end  = start+50;
  let token  = "&api_token=XXXXXXXXXXXXXXXXXXXXXX"
  

  let response = UrlFetchApp.fetch(url+start+limit+token); //
  let dataAll = JSON.parse(response.getContentText()); 
  let dataSet = dataAll;
   //Logger.log(dataSet)
  //let prices = prices;
  //create array where the data should be put
  let rows = [], data;
  if(dataSet.data === null )return
  else {
    for (let i = 0; i < dataSet.data.length; i++) {
      data = dataSet.data[i];
      let idNew = data.id; 
      rows.push([data.id, data['d93b458adf4bf84fefb6dbce477fe77cdf9de675']]);
    }
  
  Logger.log( 'function4', JSON.stringify(rows,null,2) );   // Log transformed data
  return rows;
  }
}

提前谢谢大家。

编辑：--------------FOR EACH LOOP--------- -------------------

function getPipedriveDeals(start = 0,apiRequestLimit = 39) {
  console.log("start="+start);
  //Make the initial request to get the ids you need for the details.
  var idsListRequest = "https://laptop.pipedrive.com/v1/products:(id)?start=";
  var limit = "&limit=" + apiRequestLimit;
  var token = "&api_token=XXXXXXXXXXXXXXXXXXXXXXXXXXXXX";
  var response = UrlFetchApp.fetch(idsListRequest + start + limit + token);
  var data = JSON.parse(response.getContentText()).data;
  
  //For every id in the response, construct a url (the detail url) and push to a list of requests
  var requests = [];
  console.log("data="+data);
  data.forEach(function(product) {
    var productDetailUrl = "https://laptop.pipedrive.com/v1/products/" + product.id + "/deals:(id,d93b458adf4bf84fefb6dbce477fe77cdf9de675)?start=";
    requests.push(productDetailUrl + start + limit + token)
  });
  
  //With the list of detail request urls, make one call to UrlFetchApp.fetchAll(requests)
  var responses = UrlFetchApp.fetchAll(requests);
  return [responses,JSON.parse(responses[0].getContentText()).additional_data.pagination.more_items_in_collection];
  
}

function getAllDeals(){
  var allResponses = [];
  for(var i = 0; i<500; ){ 
    var deals = getPipedriveDeals(start=i);
    deals[0].forEach((response)=>{allResponses.push(response)});
  if(deals[1]){
    // If there are more items sleep for 1000 milliseconds
    Utilities.sleep(1000);
    i+=39;
  }
  else{
    console.log("No more items in collection.");
    break;
  }
}
console.log("allResponses="+allResponses);
return allResponses;
}

关于日志中的奇怪行为：

-------------------编辑编号2------- --------------------------

直到现在我执行=getPipedriveDeals()它返回False（就像我在评论中所说的那样）以及当我尝试删除additional_data.pagination.more_items_in_collection（因为它对我来说不是很有用）我不知道为什么但是脚本不再起作用了，我在选择要返回的数据时遇到了一些困难。

---

Answer 1

您可以使用UrlFetchApp.fetchAll(requests) 来节省配额，并且可能会节省很多脚本执行时间。

我已经删除了您代码中的一些冗余，以使以下示例显示您的案例使用 fetchAll。

示例：

function getPipedriveDeals(start = 0,apiRequestLimit = 50) {
  console.log("start="+start);
  //Make the initial request to get the ids you need for the details.
  var idsListRequest = "https://laptop.pipedrive.com/v1/products:(id)?start=";
  var limit = "&limit=" + apiRequestLimit;
  var token = "&api_token=xxxxxxxxxxx";
  var response = UrlFetchApp.fetch(idsListRequest + start + limit + token);
  var data = JSON.parse(response.getContentText()).data;
  
  //For every id in the response, construct a url (the detail url) and push to a list of requests
  var requests = [];
  console.log("data="+data);
  data.forEach(function(product) {
    var productDetailUrl = "https://laptop.pipedrive.com/v1/products/" + product.id + "/deals:(id,d93b458adf4bf84fefb6dbce477fe77cdf9de675)?start=";
    requests.push(productDetailUrl + start + limit + token)
  });
  
  //With the list of detail request urls, make one call to UrlFetchApp.fetchAll(requests)
  var responses = UrlFetchApp.fetchAll(requests);
  return [responses,JSON.parse(responses[0].getContentText()).additional_data.pagination.more_items_in_collection];
}

现在假设您有一个计划，将配额限制为每 2 秒 50 个请求。

您可以将 fetchAll 调用中的请求限制为 50，并引入 delay/sleep of (X) milliseconds 以发起第二个请求，从 id=50 开始，例如：

function getAllDeals(){
  var allResponses = [];
  for(var i = 0; i<500; ){ 
    var deals = getPipedriveDeals(start=i);
    deals[0].forEach((response)=>{allResponses.push(response)});
  if(deals[1]){
    // If there are more items sleep for 1000 milliseconds
    Utilities.sleep(1000);
    i+=50;
  }
  else{
    console.log("No more items in collection.");
    break;
  }
}
console.log("allResponses="+allResponses);
return allResponses;
}