【问题标题】:Do multi level grouping and summing using Java Stream API使用 Java Stream API 进行多级分组和求和
【发布时间】:2019-07-11 13:56:54
【问题描述】:

我有课

public class Person {

    private String name;
    private String country;
    private String city;
    private String pet;
    private int totalCountryToCityCount;
    private int petCount;

    public Person(String name, String country, String city, String pet, int total, int petCount) {
        this.name = name;
        this.country = country;
        this.city = city;
        this.pet = pet;
        this.totalCountryToCityCount = total;
        this.petCount = petCount;
    }

    public String getName() {
        return name;
    }

    public String getCountry() {
        return country;
    }

    public String getCity() {
        return city;
    }

    public String getPet() {
        return pet;
    }

    public int getPetCount() {
        return petCount;
    }

    public int getTotalCountryToCityCount() {
        return totalCountryToCityCount;

    }

}

并且给定一个 Person 类的列表,我已经根据类的不同属性进行聚合。 例如 -

Person person1 = new Person("John", "USA", "NYC", "Max", 1, 2);
        Person person2 = new Person("Steve", "UK", "London", "Lucy", 2, 8);
        Person person3 = new Person("Anna", "USA", "NYC", "Max", 4, 32);
        Person person4 = new Person("Mike", "USA", "Chicago", "Duke", 5, 1);
        Person person5 = new Person("Test", "INDIA", "HYD", "Tommy", 4, 32);
        Person person6 = new Person("Test1", "INDIA", "HYD", "Tommy", 4, 65);
        Person person7 = new Person("Tim", "USA", "Chicago", "Duke", 5, 111);
        Person person8 = new Person("Tim", "USA", "Chicago", "Puke", 5, 111);
        Person person9 = new Person("Test1", "INDIA", "DELHI", "Tommy", 4, 65);
List<Person> persons = Arrays
            .asList(person1, person2, person3, person4, person5, person6, person7, person8,
                person9);

现在我需要得到一个结果,即我应该根据国家和城市的组合获得总“totalCountryToCityCount”,并且我应该根据国家、城市和宠物的组合获得总“petCount”。我可以使用 groupingBy 和 summingint 分别获取它们

private Map<String, Map<String, Integer>> getTotalCountForCountry(List<Person> persons) {
        return persons.stream().collect(groupingBy(Person::getCountry, getCityCount()));
    }

    public Collector<Person, ?, Map<String, Integer>> getCityCount() {
        return groupingBy(Person::getCity, summingInt(Person::getTotal));
    }

    public Map<String, Map<String, Map<String, Integer>>> threeLevelGrouping(List<Person> persons) {
       return  persons
            .stream().collect(
                groupingBy(Person::getCountry, groupByCityAndPetName()
                )
            );
    }

    private Collector<Person, ?, Map<String, Map<String, Integer>>> groupByCityAndPetName() {
        return groupingBy(Person::getCity, groupByPetName());
    }

    private Collector<Person, ?, Map<String, Integer>> groupByPetName() {
        return groupingBy(Person::getPet, summingInt(Person::getPetCount));
    }

给出结果

{USA={Chicago={Puke=111, Duke=112}, NYC={Max=34}}, UK={London={Lucy=8}}, INDIA={DELHI={Tommy=65}, HYD={Tommy=97}}}
{USA={Chicago=15, NYC=5}, UK={London=2}, INDIA={DELHI=4, HYD=8}}

但我想要的实际结果是:-

{USA={Chicago={15,{Puke=111, Duke=112}}, NYC={5,{Max=34} }, UK={London={2, {Lucy=8}}, INDIA={DELHI={4, {Tommy=65}}, , HYD={8,{Tommy=97}}}}

有没有办法使用 Java 流 API 实现相同的功能

我也尝试过使用代码 -

 personList.stream().collect(groupingBy(person -> person.getCountry(), collectingAndThen(reducing(
            (a, b) -> new Person(a.getName(), a.getCountry(), a.getCity(), a.getPet(),
                a.getTotal() + b.getTotal(), a.getPetCount() + b.getPetCount())),
            Optional::get)))
            .forEach((country, person) -> System.out.println(country + person));

但是得到了结果 -

USAPerson{name='John', country='USA', city='NYC'}
UKPerson{name='Steve', country='UK', city='London'}
INDIAPerson{name='Test', country='INDIA', city='HYD'}

令人惊讶地删除了计数

【问题讨论】:

  • 但是15 & {Puke=111, Duke=112} 不是同一类型。您等待什么结果类型?
  • 我需要基于 country 、 city 和 petCount 的总宠物数的聚合(总和)以及基于 country 和 city 的另一个总和(totalCountryToCityCount)。能够通过使用我在此处的代码部分中添加的两个不同的收集器来获得。但它可以在一次迭代中完成
  • 我明白了,但是 15int{Puke=111, Duke=112}Map&lt;String, Integer&gt;... 所以你的结果会像 Map&lt;String, Map&lt;String, Object&gt;&gt;.. 这样可以吗?
  • 是的,只要我能得到所需的结果就可以了
  • Person 不编译,顺便说一句。并且不要使用new Integer(...)

标签: java java-stream collectors multi-level


【解决方案1】:

您真正要找的是Collectors::teeing,但仅在java-12 中可用:

System.out.println(
        persons.stream()
               .collect(Collectors.groupingBy(
                   Person::getCountry,
                   Collectors.groupingBy(
                       Person::getCity,
                       Collectors.teeing(
                           Collectors.summingInt(Person::getTotalCountryToCityCount),
                           Collectors.groupingBy(
                               Person::getPet,
                               Collectors.summingInt(Person::getPetCount)
                           ),
                           SimpleEntry::new
                       )
                   ))));

java-8 的后端端口可用here

【讨论】:

  • @YassinHajaj {USA={Chicago=15={Puke=111, Duke=112}, NYC=5={Max=34}}, UK={London=2={Lucy=8}}, INDIA={DELHI=4={Tommy=65}, HYD=8={Tommy=97}}}
  • 与 OP 的要求有点不同,但希望他能接受 :) {USA={Chicago={15,{Puke=111, Duke=112}}, NYC={5,{Max=34} }, UK={London={2, {Lucy=8}}, INDIA={DELHI={4, {Tommy=65}}, , HYD={8,{Tommy=97}}}}
  • @YassinHajaj 这是只是在不同的格式下,因为SimplerEntry::new,它可以通过(left, right) -&gt; left + "," + right来代替。
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