实体映射中的重复列：Hiv_AnswerForEntities 列：variant_id（应使用 insert="false" update="false" 进行映射）

Question

我在 ORM 中遇到继承问题。

我使用 JPA/hibernate。我收到一个我不明白的错误。我已经声明了一次专栏，但错误告诉我我已经这样做了两次。它可能会以某种方式与继承混淆。 但我不知道为什么。请帮忙

我得到的错误：

Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: myInsurance.models.liability.hivAndVHProtection.Hiv_AnswerForEntities column: variant_id (should be mapped with insert="false" update="false")

实体代码：

@MappedSuperclass
@Inheritance(strategy=InheritanceType.TABLE_PER_CLASS)
public class Answer extends Generic<Answer> {
    @OneToOne public Variant variant;

}

@Entity
@DiscriminatorValue("Answer")
@Table(name="mi__Liability_Part_Hiv_Answer")
@Inheritance(strategy=InheritanceType.SINGLE_TABLE)
public class Hiv_Answer extends Answer {
    @OneToOne public HivAndVHProtection_Variant variant;
}

@Entity
@DiscriminatorValue("AnswerForEntities")
public class Hiv_AnswerForEntities extends Hiv_Answer {

    public int proffesionGroup;
    public int personCount;
    public int contributionPerPerson;
    @Transient public int totalContribution;
}

以及完整的堆栈跟踪：

play.api.UnexpectedException: Unexpected exception[PersistenceException: [PersistenceUnit: defaultPersistenceUnit] Unable to build EntityManagerFactory]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:148) ~[play_2.10.jar:2.2.6]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:112) ~[play_2.10.jar:2.2.6]
        at scala.Option.map(Option.scala:145) ~[scala-library.jar:na]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1.apply(ApplicationProvider.scala:112) ~[play_2.10.jar:2.2.6]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1.apply(ApplicationProvider.scala:110) ~[play_2.10.jar:2.2.6]
        at scala.util.Success.flatMap(Try.scala:200) ~[scala-library.jar:na]
        at play.core.ReloadableApplication$$anonfun$get$1.apply(ApplicationProvider.scala:110) ~[play_2.10.jar:2.2.6]
        at play.core.ReloadableApplication$$anonfun$get$1.apply(ApplicationProvider.scala:102) ~[play_2.10.jar:2.2.6]
        at scala.concurrent.impl.Future$PromiseCompletingRunnable.liftedTree1$1(Future.scala:24) ~[scala-library.jar:na]
        at scala.concurrent.impl.Future$PromiseCompletingRunnable.run(Future.scala:24) ~[scala-library.jar:na]
        at scala.concurrent.forkjoin.ForkJoinTask$AdaptedRunnableAction.exec(ForkJoinTask.java:1361) ~[scala-library.jar:na]
        at scala.concurrent.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:260) ~[scala-library.jar:na]
        at scala.concurrent.forkjoin.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:1339) ~[scala-library.jar:na]
        at scala.concurrent.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1979) ~[scala-library.jar:na]
        at scala.concurrent.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:107) ~[scala-library.jar:na]
Caused by: javax.persistence.PersistenceException: [PersistenceUnit: defaultPersistenceUnit] Unable to build EntityManagerFactory
        at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:915) ~[hibernate-entitymanager-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:890) ~[hibernate-entitymanager-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:57) ~[hibernate-entitymanager-4.2.0.CR1.jar:4.2.0.CR1]
        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:63) ~[hibernate-jpa-2.0-api.jar:1.0.1.Final]
        at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:47) ~[hibernate-jpa-2.0-api.jar:1.0.1.Final]
        at play.db.jpa.JPAPlugin.onStart(JPAPlugin.java:35) ~[play-java-jpa_2.10.jar:2.2.6]
        at play.api.Play$$anonfun$start$1$$anonfun$apply$mcV$sp$1.apply(Play.scala:88) ~[play_2.10.jar:2.2.6]
        at play.api.Play$$anonfun$start$1$$anonfun$apply$mcV$sp$1.apply(Play.scala:88) ~[play_2.10.jar:2.2.6]
        at scala.collection.immutable.List.foreach(List.scala:318) ~[scala-library.jar:na]
        at play.api.Play$$anonfun$start$1.apply$mcV$sp(Play.scala:88) ~[play_2.10.jar:2.2.6]
        at play.api.Play$$anonfun$start$1.apply(Play.scala:88) ~[play_2.10.jar:2.2.6]
        at play.api.Play$$anonfun$start$1.apply(Play.scala:88) ~[play_2.10.jar:2.2.6]
        at play.utils.Threads$.withContextClassLoader(Threads.scala:18) ~[play_2.10.jar:2.2.6]
        at play.api.Play$.start(Play.scala:87) ~[play_2.10.jar:2.2.6]
        at play.core.ReloadableApplication$$anonfun$get$1$$anonfun$apply$1$$anonfun$1.apply(ApplicationProvider.scala:139) ~[play_2.10.jar:2.2.6]
        ... 14 common frames omitted
Caused by: org.hibernate.MappingException: Repeated column in mapping for entity: myInsurance.models.liability.hivAndVHProtection.Hiv_AnswerForEntities column: variant_id (should be mapped with insert="false" update="false")
        at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:682) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.mapping.PersistentClass.checkPropertyColumnDuplication(PersistentClass.java:704) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.mapping.PersistentClass.checkColumnDuplication(PersistentClass.java:726) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.mapping.PersistentClass.validate(PersistentClass.java:479) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.mapping.UnionSubclass.validate(UnionSubclass.java:61) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.cfg.Configuration.validate(Configuration.java:1283) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1734) ~[hibernate-core-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.ejb.EntityManagerFactoryImpl.<init>(EntityManagerFactoryImpl.java:94) ~[hibernate-entitymanager-4.2.0.CR1.jar:4.2.0.CR1]
        at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:905) ~[hibernate-entitymanager-4.2.0.CR1.jar:4.2.0.CR1]
        ... 28 common frames omitted

--编辑--

我在Entities 中使用 As 关系的所有 Variant 类

@Entity
@Inheritance(strategy=InheritanceType.TABLE_PER_CLASS)
public class Variant extends GenericDictionary<Variant> {}

@Entity
@Table(name="mi__Liability_Part_Hiv_Var")
public class HivAndVHProtection_Variant extends Variant {
    @OneToMany public List<HivAndVHProtection_VariantValue> hivAndVHProtection_VariantValue = new LinkedList<HivAndVHProtection_VariantValue>();
}

@Entity
@Table(name="mi__Liability_Part_Legal_Var")
public class LegalExpensesInsurance_Variant extends GenericDictionary<LegalExpensesInsurance_Variant> {
    @OneToMany private List<LegalExpensesInsurance_VariantValue> legalExpensesInsurance_VariantValues = new LinkedList<LegalExpensesInsurance_VariantValue>();
}

所有这些Variant 类都扩展了超类Variant

我也试过： @OneToOne public Class<? extends Variant> variant; 但出现错误：

Caused by: org.hibernate.AnnotationException: @OneToOne or @ManyToOne on myInsurance.models.liability.hivAndVHProtection.Hiv_Answer.variant references an unknown entity: java.lang.Class

Answer 1

在Answer 你有

@OneToOne public Variant variant;

在Hiv_Answer 你有

@OneToOne public HivAndVHProtection_Variant variant;

这两个映射的连接列名称默认为variant_id，在这种情况下，JPA 会强制您用insertable = "false", updateable = "false" 标记其中一个，因为您无法通过多个映射维护同一个字段。

您的选择是：

1. 在这些映射之一中将变量名称 variant 更改为其他名称（首选）
2. 在至少一个映射上使用@JoinColumn 以指定不同的连接列而不是默认的连接列 (variant_id)