【发布时间】:2017-08-01 09:52:38
【问题描述】:
我正在尝试编写一个实用程序 java 程序,它在 unix 框中调用 perl 脚本并显示脚本的输出。问题是当我执行command2时,
String[] command2 = {"/archive/scripts/grep.pl", "/apps/ws/logs/api.log"};
输出正确。但是当我使用command1时,
String[] command1 = {"/archive/scripts/grep.pl", "/apps/ws/logs/*"};
我得到以下异常:
Can't open /apps/ws/logs/*: No such file or directory at /archive/scripts/grep.pl line 160.
以下是完整代码供您参考:
StringBuffer output = new StringBuffer();
try {
ProcessBuilder processBuilder = new ProcessBuilder(command1);
LOGGER.debug("Command: "+processBuilder.command());
Process process = processBuilder.start();
process.waitFor();
BufferedReader br;
if (process.exitValue() == 0) {
LOGGER.debug("Inside if block. Exit value: "+process.exitValue());
String line;
br = new BufferedReader(new InputStreamReader(process.getErrorStream()));
while ((line = br.readLine()) != null) {
output.append(line + "\n");
}
} else {
LOGGER.debug("Inside Else block. Exit value: "+process.exitValue());
br = new BufferedReader(new InputStreamReader(process.getInputStream()));
String line;
while ((line = br.readLine()) != null) {
output.append(line + "\n");
}
}
} catch (Exception e) {
LOGGER.debug("Exception thrown"+e.getStackTrace());
output.append(e.getStackTrace().toString());
e.printStackTrace();
}
return output.toString();
我无法理解问题所在。有没有办法做到这一点。
【问题讨论】:
-
该目录下是否有名称为
*的文件?文件掩码由 shell 解析。如果直接执行脚本,shell就被忽略了... -
没有名为
*的文件。当我在框中运行命令/archive/scripts/grep.pl /apps/ws/logs/*时,我得到了正确的输出。
标签: java unix wildcard processbuilder