在 Typesafe Activator 命令行中创建新应用程序时出现 TimeoutException

Question

每次我尝试使用 typesafe activator 命令行创建新应用程序时都会遇到以下错误。通过 Activator UI，它工作正常，并且在 Fedora20 中使用 Typesafe Activator 1.0.10。

Enter an application name
> hello-scala
Futures timed out after [6 seconds]
java.util.concurrent.TimeoutException: Futures timed out after [6 seconds]
    at scala.concurrent.impl.Promise$DefaultPromise.ready(Promise.scala:96)
    at scala.concurrent.impl.Promise$DefaultPromise.result(Promise.scala:100)
    at scala.concurrent.Await$$anonfun$result$1.apply(package.scala:107)
    at scala.concurrent.BlockContext$DefaultBlockContext$.blockOn(BlockContext.scala:53)
    at scala.concurrent.Await$.result(package.scala:107)
    at activator.ActivatorCli$$anonfun$apply$1.apply$mcI$sp(ActivatorCli.scala:32)
    at activator.ActivatorCli$$anonfun$apply$1.apply(ActivatorCli.scala:17)
    at activator.ActivatorCli$$anonfun$apply$1.apply(ActivatorCli.scala:17)
    at activator.ActivatorCli$.withContextClassloader(ActivatorCli.scala:127)
    at activator.ActivatorCli$.apply(ActivatorCli.scala:17)
    at activator.ActivatorLauncher.run(ActivatorLauncher.scala:27)
    at xsbt.boot.Launch$$anonfun$run$1.apply(Launch.scala:57)
    at xsbt.boot.Launch$.withContextLoader(Launch.scala:77)
    at xsbt.boot.Launch$.run(Launch.scala:57)
    at xsbt.boot.Launch$$anonfun$explicit$1.apply(Launch.scala:45)
    at xsbt.boot.Launch$.launch(Launch.scala:65)
    at xsbt.boot.Launch$.apply(Launch.scala:16)
    at xsbt.boot.Boot$.runImpl(Boot.scala:32)
    at xsbt.boot.Boot$.main(Boot.scala:21)
    at xsbt.boot.Boot.main(Boot.scala)

Answer 1

这已通过最新的 Activator 解决：https://github.com/typesafehub/activator/issues/225

下载：http://typesafe.com/platform/getstarted