为什么我不能将 datetime.timedelta 除以浮点数？

Question

>>> import datetime
>>> now1 = datetime.datetime.now()
>>> now2 = datetime.datetime.now()
>>> timedelta = now2-now1
>>> halfdt = timedelta/2  #This works just fine
>>> halfdt = timedelta/2. #TypeError: unsupported operand type(s) for /: 'datetime.timedelta' and 'float'

有人知道只允许时间增量可以被整数整除的原因吗？

Answer 1

其实很简单 - 它是一个缺失的功能。

这样做的好处是它已作为一个功能添加到 Python 3.x 中。

注意2.x和3.x中支持的运算表的区别。

Answer 2

非常有趣——我原以为这也能奏效。我刚刚用 Python 2.x 中的一些示例/文档测试编写了一个函数。也发布为ActiveState recipe：

import datetime

def divide_timedelta(td, divisor):
    """Python 2.x timedelta doesn't support division by float, this function does.

    >>> td = datetime.timedelta(10, 100, 1000)
    >>> divide_timedelta(td, 2) == td / 2
    True
    >>> divide_timedelta(td, 100) == td / 100
    True
    >>> divide_timedelta(td, 0.5)
    datetime.timedelta(20, 200, 2000)
    >>> divide_timedelta(td, 0.3)
    datetime.timedelta(33, 29133, 336667)
    >>> divide_timedelta(td, 2.5)
    datetime.timedelta(4, 40, 400)
    >>> td / 0.5
    Traceback (most recent call last):
      ...
    TypeError: unsupported operand type(s) for /: 'datetime.timedelta' and 'float'

    """
    # timedelta.total_seconds() is new in Python version 2.7, so don't use it
    total_seconds = (td.microseconds + (td.seconds + td.days * 24 * 3600) * 1e6) / 1e6
    divided_seconds = total_seconds / float(divisor)
    return datetime.timedelta(seconds=divided_seconds)

if __name__ == '__main__':
    import doctest
    doctest.testmod()