【发布时间】:2016-01-18 06:01:03
【问题描述】:
我想从这里分组日期和时间:
Mon : array(9:00AM - 11:00AM, 1:00pm-6pm)
Tue : array(8:00AM - 11:00AM,12:00pm-6pm)
Wed : array(9:00AM - 11:00AM, 1:00pm-6pm)
Thu : array(9:00AM - 11:00AM,1:00pm-6pm)
Fri : array(9:00AM - 12:00PM,1:00pm-6pm)
Sat : array(9:00AM - 7:00PM)
Sun : array(9:00AM - 12:00AM,1:00pm-6pm)
预期结果:
Mon,wed,thu - 9:00AM - 11:00aM
1:00pm-6pm
tue : 8:00AM - 11:00am
12:00pm-6pm
fri,sun - 9:00AM - 12:00PM
1:00pm-6pm
sat: 9:00AM -7:00pm
下面是我正在尝试解决的代码。
$open_Hours = 数组(
'周一' => 数组('9:00AM - 11:00AM', '1:00pm-6pm'),
'周二' => 数组('8:00AM - 11:00AM', '12:00pm-6pm'),
'星期三' => 数组('9:00AM - 11:00AM', '1:00pm-6pm'),
'周四' => 数组('9:00AM - 11:00AM','1:00pm-6pm'),
'星期五' => 数组('9:00AM - 12:00PM','1:00pm-6pm'),
'星期六' => 数组('9:00AM - 7:00PM'),
'太阳' => 数组('9:00AM - 12:00AM','1:00pm-6pm')
);
foreach($open_Hours as $k => $v){
$open_array[$v][] = $k;
}
foreach($open_array as $time => $days){
回声内爆(“,”,$天)。 “”。 $时间。 PHP_EOL;
}
【问题讨论】:
-
你是如何超越数组的?
-
代码不工作。您的任何初始代码和留下的东西都不匹配。在代码中,您没有提到上面存在的周一和其他日子的晚上时间。请检查这两件事。然后你可以比较数组的值。虽然可以互相匹配。如果您需要我,我随时准备帮助您编写代码。
-
** 我想要输出:周一,周三,周四 - 上午 9:00 - 上午 11:00 周二:上午 8:00 - 上午 11:00 下午 12:00 - 下午 6 点**周五,太阳 - 9:00 AM - 12:00 PM 1:00 PM - 6 PM 周六:9:00 AM -7:00 PM
-
@– Charanjeet Singh : 帮帮我
-
将
$open_array[$v][] = $k;更改为foreach ($val as $v1) { $open_array[$v1][] = $k;}