从 url 列表下载视频 (python)

Question

我有一个网址列表（示例网址），每个网址都包含一个视频：

urls = ['https://...live.com/archive/player?live_id=9368953&artist_id=44176&type=1', 'https://...live.com/archive/player?live_id=9344610&artist_id=44176&type=1']

每个 url 都有以下检查元素：

<div class="row">
  <div class="clearfix">
    <button type="button" class="btn btn-primary" onclick="location.href='https://...video.net/archive/flv/master/0009368953-44176.flv?Policy=a19_&Key-Pair-Id=PN2'"></button>
  </div>
</div>

对于每个 url，我想获取其 location.href 的链接（在本例中为“https://...video.net/archive/flv/master/0009368953-44176.flv?Policy=a19_&Key-Pair-Id=PN2”），并从这些链接下载视频。

提前谢谢你！

Answer 1

import requests
from bs4 import BeautifulSoup


lid = [9368953, 9344610]
aid = [44176, 44176]


def main(url):
    with requests.Session() as req:
        for x, y in zip(lid, aid):
            r = req.get(url.format(x, y))
            soup = BeautifulSoup(r.content, 'html.parser')
            target = soup.select_one("button.btn.btn-primary")['onclick'].split("'")[1]
            r = req.get(target)

            with open(f"{aid}.flv", 'wb') as f:
                f.write(r.content)


main("https://ope.live.com/archive/player?live_id={}&artist_id={}&type=1")