空的 .json 文件

Question

我编写了这个简短的蜘蛛代码来从黑客新闻首页(http://news.ycombinator.com/) 中提取标题。

import scrapy

class HackerItem(scrapy.Item): #declaring the item
    hackertitle = scrapy.Field()


class HackerSpider(scrapy.Spider):
    name = 'hackernewscrawler'
    allowed_domains = ['news.ycombinator.com'] # website we chose
    start_urls = ['http://news.ycombinator.com/']

   def parse(self,response):
        sel = scrapy.Selector(response) #selector to help us extract the titles
        item=HackerItem() #the item declared up

# xpath of the titles
        item['hackertitle'] = 
sel.xpath("//tr[@class='athing']/td[3]/a[@href]/text()").extract()


# printing titles using print statement.
        print (item['hackertitle']

但是当我运行代码scrapy scrawl hackernewscrawler -o hntitles.json -t json

我得到一个没有任何内容的空 .json 文件。

Answer 1

您应该将print 语句更改为yield：

import scrapy

class HackerItem(scrapy.Item): #declaring the item
    hackertitle = scrapy.Field()


class HackerSpider(scrapy.Spider):
    name = 'hackernewscrawler'
    allowed_domains = ['news.ycombinator.com'] # website we chose
    start_urls = ['http://news.ycombinator.com/']

    def parse(self,response):
        sel = scrapy.Selector(response) #selector to help us extract the titles
        item=HackerItem() #the item declared up

# xpath of the titles
        item['hackertitle'] = sel.xpath("//tr[@class='athing']/td[3]/a[@href]/text()").extract()


# return items
        yield item

然后运行：

scrapy crawl hackernewscrawler -o hntitles.json -t json