使用 PHP Simple HTML DOM Parser 查找带有类的 div，它是纯文本答案

【问题标题】：Find div with class and it's plain-text using PHP Simple HTML DOM Parser使用 PHP Simple HTML DOM Parser 查找带有类的 div，它是纯文本
【发布时间】：2018-05-05 15:15:04
【问题描述】：

我想在 Work Experience 和 EDUCATION AND TRAINING 之间找到课程 ft00，并从给定的 html 中提取包含日期的课程文本 p>

<p class = "ft00">Introduction</p>
<p class = "ft00">John Smith</p>
<p class = "ft02">Email:</p>
<p class = "ft00">John@gmail.com</p>
<p class = "ft00">Work Experience</p>
<p class = "ft00">27 July 2017</p>
<p class = "ft02">ABC Company</p>
<p class = "ft00">19 May 2018</p>
<p class ="ft02">XYZ Company</p>
<p class = "ft00">EDUCATION AND TRAINING</p>

到目前为止，我能得到的是提取 工作经验 和 教育和培训 之间的所有数据，它工作正常，代码如下：-

$fexp = $html->find('p[plaintext^=Work Experience]');
$items = array();
 foreach ($fexp as $keye) {

    while ( $keye->nextSibling() ) {
        if ( $keye->nextSibling() == TRUE ) {

         $keye = $keye->nextSibling();
            $varce = $keye->plaintext;



        }
        if ( trim($varce) == "EDUCATION AND TRAINING" ){
            break;
        }
        //$test[] = $collection;
       $items[] = $varce;
        // echo $varce;

}
}
var_dump($items);

我很接近但似乎无法找到解决方案，任何帮助将不胜感激谢谢:-)

【问题讨论】：

明确你的问题
@PreciousTom 哪一部分你没有得到？

标签： php html parsing web-scraping simple-html-dom

【解决方案1】：

使用DOMDocument 和DOMXPath，您可以像下面这样进行操作，我从未使用过 Simple HTML DOM Parser，但我认为它具有 XPath。

<?php
$dom = new DOMDocument();

$dom->loadHtml('
<p class = "ft00">Introduction</p>
<p class = "ft00">John Smith</p>
<p class = "ft02">Email:</p>
<p class = "ft00">John@gmail.com</p>
<p class = "ft00">Work Experience</p>
<p class = "ft00">27 July 2017</p>
<p class = "ft02">ABC Company</p>
<p class = "ft00">19 May 2018</p>
<p class ="ft02">XYZ Company</p>
<p class = "ft00">EDUCATION AND TRAINING</p>
', LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXPath($dom);

$result = [];
$matching  = false;
foreach ($xpath->query("//p[contains(@class, 'ft00') or contains(@class, 'ft02')]/text()") as $p) {
    if ($p->nodeValue === 'Work Experience' || $matching) {
        $result[] = $p->nodeValue;
        $matching = true;
    }
    if ($p->nodeValue === 'EDUCATION AND TRAINING') {
        break;
    }
}

print_r($result);

结果：

Array
(
    [0] => Work Experience
    [1] => 27 July 2017
    [2] => ABC Company
    [3] => 19 May 2018
    [4] => XYZ Company
    [5] => EDUCATION AND TRAINING
)

https://3v4l.org/0nvr4

【讨论】：

感谢我使用了与您相同的逻辑并使用简单的 html dom 实现它，它工作正常。

【解决方案2】：

这是正确的工作代码：-

$test = array();
$matching  = false;
$collection = $html->find('p.ft00');
foreach ($collection as $tkey) {
    if ($tkey->plaintext == "WORK EXPERIENCE" || $matching ) {
        $test[] = $tkey->plaintext;
        $matching = true;
    }
    if ( $tkey->plaintext == "EDUCATION AND TRAINING") {
        break;
    }

    }
    var_dump($test);

输出：-

Array
(
    [0] => Work Experience
    [1] => 27 July 2017
    [2] => 19 May 2018
    [3] => EDUCATION AND TRAINING
)

【讨论】：