【发布时间】:2019-12-11 10:57:25
【问题描述】:
我有以下代码,作为 POST 请求按预期工作(给定正确的 URL 等)。似乎我在阅读状态码时遇到了问题(我收到了成功的 201,并且基于该数字我需要继续处理)。知道如何获取状态码吗?
static async Task CreateConsentAsync(Uri HTTPaddress, ConsentHeaders cconsentHeaders, ConsentBody cconsent)
{
HttpClient client = new HttpClient();
try
{
client.BaseAddress = HTTPaddress;
client.DefaultRequestHeaders.Accept.Clear();
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("*/*"));
client.DefaultRequestHeaders.Add("Connection", "keep-alive");
client.DefaultRequestHeaders.Add("Cache-Control", "no-cache");
client.DefaultRequestHeaders.Add("otherHeader", myValue);
//etc. more headers added, as needed...
HttpRequestMessage request = new HttpRequestMessage(HttpMethod.Post, client.BaseAddress);
request.Content = new StringContent(JsonConvert.SerializeObject(cconsent, Formatting.Indented), System.Text.Encoding.UTF8, "application/json");
Console.WriteLine("\r\n" + "POST Request:\r\n" + client.DefaultRequestHeaders + "\r\nBody:\r\n" + JsonConvert.SerializeObject(cconsent, Formatting.Indented) + "\r\n");
await client.SendAsync(request).ContinueWith
(
responseTask =>
{
Console.WriteLine("Response: {0}", responseTask.Result + "\r\nBody:\r\n" + responseTask.Result.Content.ReadAsStringAsync().Result);
}
);
Console.ReadLine();
}
catch (Exception e)
{
Console.WriteLine("Error in " + e.TargetSite + "\r\n" + e.Message);
Console.ReadLine();
}
}
【问题讨论】:
-
你已经在
async函数中,所以你不需要使用ContinueWith。
标签: c# api httprequest