Retrofit+GSON 的正确 JSON 响应？

Question

我对我的一项网络服务有以下响应，我正在使用 Retrofit 和 GSON。

    {
    "error": false,
    "Timeline": {
        "Date": "2040-06-15",
        "bandList": {
            "breakfast": {
                "dosageList": {
                    "01": {
                        "packed": "true",
                        "medicineList": [
                            {
                                "medicine": {
                                    "id": "01",
                                    "name": "glipizide 5 mg tablet, 100 ",
                                    "category": "regular",
                                    "image": null,
                                    "indication": "NIDDM",
                                    "packed": true,
                                    "med_id": "352",
                                    "dosage": 1
                                }
                            },
                            {
                                "medicine": {
                                    "id": "04",
                                    "name": "Frusemide (Terry White Chemists) 20 mg uncoated tablet, 100 ",
                                    "category": "regular",
                                    "image": null,
                                    "indication": "Fluid",
                                    "packed": true,
                                    "med_id": "4",
                                    "dosage": 2
                                }
                            }
                        ]
                    },
                    "02": {
                        "packed": "false",
                        "medicineList": [
                            {
                                "medicine": {
                                    "id": "05",
                                    "name": "Refresh Tears Plus 0.5% eye drops solution, 15 mL ",
                                    "category": "regular",
                                    "image": null,
                                    "indication": "Dry Eyes",
                                    "packed": false,
                                    "med_id": "372",
                                    "dosage": 1
                                }
                            }
                        ]
                    }
                }
            }
        }
    }
}

第一季度。 有没有办法使用模型类（POJO）或不使用它们来解析上述响应？我坚持为上述结构生成模型类。如何为上述 JSON 生成 POJO？

第二季度。我处于如何说服发送以下响应的位置，JSON 的正确结构/格式是什么？是否有任何 JSON 标准可以向 Web 开发人员展示以获取这种 JSON 格式？ （注：我可以解析这个结构）

{
"error": false,
"Timeline": {
    "Date": "2040-06-15",
    "band": [
        {
            "name": "breakfast",
            "dosage": [
                {
                    "id": "01",
                    "packed": "true",
                    "medicine": [
                        {
                            "id": "01",
                            "name": "glipizide 5 mg tablet, 100 ",
                            "category": "regular",
                            "image": null,
                            "indication": "NIDDM",
                            "packed": true,
                            "med_id": "52",
                            "dosage": 1
                        },
                        {
                            "id": "04",
                            "name": "Frusemide (Terry White Chemists) 20 mg uncoated tablet, 100 ",
                            "category": "regular",
                            "image": null,
                            "indication": "Fluid",
                            "packed": true,
                            "med_id": "54",
                            "dosage": 2
                        }
                    ]
                },
                {
                    "id": "02",
                    "packed": "false",
                    "medicine": [
                        {
                            "id": "05",
                            "name": "Refresh Tears Plus 0.5% eye drops solution, 15 mL ",
                            "category": "regular",
                            "image": null,
                            "indication": "Dry Eyes",
                            "packed": false,
                            "med_id": "372",
                            "dosage": 1
                        }
                    ]
                }
            ]
        }
    ]
}

}

提前谢谢你。

编辑

我曾经使用这些站点自动生成 POJO，但它对某些类给出了以下响应。如何将其转换为正确的类？

package ;
public class DosageList
{
    private 01 01;

    private 02 02;

    public void set01(01 01){
        this.01 = 01;
    }
    public 01 get01(){
        return this.01;
    }
    public void set02(02 02){
        this.02 = 02;
    }
    public 02 get02(){
        return this.02;
    }
}

编辑 2

我几乎完成了第一个 JSON 的解析，但卡在了这里。

for (String bandName: event.getTimeline().getBand().keySet()) {

  Log.d("<<<--Band-->>>", "Value " + event.getTimeline().getBand().get(bandName));
  Band band = event.getTimeline().getBand().get(bandName);
  for (String dosageName:band.getDosage().keySet()) {
     Dosage dosage = band.getDosage().get(dosageName);
     Log.d("<<<--Dosage-->>>", "Value " + dosage.getMedicine());
          for (Medicine medicine: dosage.getMedicine()) {
               Log.d("<<<--Medicine-->>>", "Value " + dosage.getMedicine().get(0));
          }
   }

}

如何检索医学值？

Answer 1

 public class Medicine
     {
    private String id;

private String name;

private String category;

private String image;

private String indication;

private boolean packed;

private String med_id;

private int dosage;

public void setId(String id){
    this.id = id;
}
public String getId(){
    return this.id;
}
public void setName(String name){
    this.name = name;
}
public String getName(){
    return this.name;
}
public void setCategory(String category){
    this.category = category;
}
public String getCategory(){
    return this.category;
}
public void setImage(String image){
    this.image = image;
}
public String getImage(){
    return this.image;
}
public void setIndication(String indication){
    this.indication = indication;
}
public String getIndication(){
    return this.indication;
}
public void setPacked(boolean packed){
    this.packed = packed;
}
public boolean getPacked(){
    return this.packed;
}
public void setMed_id(String med_id){
    this.med_id = med_id;
}
public String getMed_id(){
    return this.med_id;
}
public void setDosage(int dosage){
    this.dosage = dosage;
}
public int getDosage(){
    return this.dosage;
}
}






   import java.util.ArrayList;
 import java.util.List;
 public class Dosage
  {
private String id;

private String packed;

private List<Medicine> medicine;

public void setId(String id){
    this.id = id;
}
public String getId(){
    return this.id;
}
public void setPacked(String packed){
    this.packed = packed;
}
public String getPacked(){
    return this.packed;
}
public void setMedicine(List<Medicine> medicine){
    this.medicine = medicine;
}
public List<Medicine> getMedicine(){
    return this.medicine;
}
 }


 import java.util.ArrayList;
 import java.util.List;
 public class Band
  {
private String name;

private List<Dosage> dosage;

public void setName(String name){
    this.name = name;
}
public String getName(){
    return this.name;
}
public void setDosage(List<Dosage> dosage){
    this.dosage = dosage;
}
public List<Dosage> getDosage(){
    return this.dosage;
}
  }


 import java.util.ArrayList;
  import java.util.List;
   public class Timeline
  {
private DateTime Date;

private List<Band> band;

public void setDate(DateTime Date){
    this.Date = Date;
}
public DateTime getDate(){
    return this.Date;
}
public void setBand(List<Band> band){
    this.band = band;
}
public List<Band> getBand(){
    return this.band;
}
 }


 public class Root
 {
private boolean error;

private Timeline Timeline;

public void setError(boolean error){
    this.error = error;
}
public boolean getError(){
    return this.error;
}
public void setTimeline(Timeline Timeline){
    this.Timeline = Timeline;
}
public Timeline getTimeline(){
    return this.Timeline;
}
  }

...享受...

Answer 2

第一个问题：

您可以在没有 POJO 类的情况下解析 JSON，但建议使用 他们和关于你坚持从 JSON 生成它们 你可以用jsonschema2pojo我想 这是最好的。

第二个：

是的，有 JSON 标准，您可以在 JSON 网站上找到它们。

Answer 3

第 1 步：首先从我能看到的最里面的 json 对象开始，它是“药”

创建一个类似这样的 POJO 类

public class Medicine implements android.os.Parcelable {

@SerializedName("id")
private String id;

// Getter setter method for id
// Do it for all the JSON tags

}

第 2 步：为“medicineList”创建一个类，这有点像这样

public class MedicineList implements Parcelable {

@SerializedName("medicineList")
private List<Medicine > medicine;

// Getter setter can go here
}

以类似的方式，在 JSON 响应中移动到您的基本标记。这让我很容易理解。我不会发布完整的解决方案，因为那是你在 EOD 的作业。

Answer 4

第一季度的解决方案 -

是的，您可以通过在 Android Studio 中安装 DTO 插件，使用模型类解析上述响应。该插件将自动为响应创建 POJO 类。