如何使用 gson 和 volley 解析嵌套的 json？

Question

这是我要使用的json数据：

{
     "name" : "Ravi Tamada", 
     "email" : "ravi8x@gmail.com",
     "phone" : 
      {
         "home" : "08947 000000",
         "mobile" : "9999999999"
      }

}

---

这是我的 JsonObjectRequest：

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject jsonObject) {

            Gson gson = new Gson();
            People people;
            people = gson.fromJson(jsonObject.toString(),People.class);
            tv_city.setText(""+people.email);

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError volleyError) {



        }
    });

用 tv_city.setText(""+people.email()) 没问题...

---

这是我的 javabean 类：

public class People {

    public String name ;
    public String email;

    public class Phone{
        public String home;
        public String mobile;

    }

}

---

现在我想得到“家”号，怎么办？

Answer 1

1- 您必须按如下方式更新您的 bean 类：-

public class People implements Serializable {
private String name ;
private String email;
private Phone phone;

 public Phone getPhone () {
    return phone;
}

public void setPhone (Phone phone) {
    this.phone = phone;
}
public String getName () {
    return name;
}

public void setName (String name) {
    this.name = name;
}

public String getEmail () {
    return email;
}

public void setEmail (String email) {
    this.email = email;
}}

2- 创建一个新的 bean 类 Phone.java :-

public class Phone implements Serializable{
private String home;

public String getMobile () {
    return mobile;
}

public void setMobile (String mobile) {
    this.mobile = mobile;
}

public String getHome () {
    return home;
}

public void setHome (String home) {
    this.home = home;
}

private String mobile;}

3- 现在更新您的代码如下：-

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

    @Override
    public void onResponse(JSONObject jsonObject) {

        Gson gson = new Gson();
        People people;
        people = gson.fromJson(jsonObject.toString(),People.class);
        tv_city.setText(""+people.email);
        //for getting Home & Mobile number
          String home=people.getPhone.getHome();
          String mobile=people.getPhone.getMobile();

    }
}, new Response.ErrorListener() {
    @Override
    public void onErrorResponse(VolleyError volleyError) {



    }
});

注意：- 我上面的 bean 符合您问题中预期的 api 响应。但是，如果您有嵌套对象，那么您必须在 People bean 中选择 List<Phone> 或 ArrayList<Phone>，然后创建它的 getter 和 setter。

希望对你有帮助！！！

Answer 2

将您的 JavaBean 类替换为

public class People {

@SerializedName("name")
@Expose
private String name;
@SerializedName("email")
@Expose
private String email;
@SerializedName("phone")
@Expose

private Phone phone;

/**
* 
* @return
* The name
*/
public String getName() {
return name;
}

/**
* 
* @param name
* The name
*/
public void setName(String name) {
this.name = name;
}

/**
* 
* @return
* The email
*/
public String getEmail() {
return email;
}

/**
* 
* @param email
* The email
*/
public void setEmail(String email) {
this.email = email;
}

/**
* 
* @return
* The phone
*/
public Phone getPhone() {
return phone;
}

/**
* 
* @param phone
* The phone
*/
public void setPhone(Phone phone) {
this.phone = phone;
}

}

还有

public class Phone {

@SerializedName("home")
@Expose
private String home;
@SerializedName("mobile")
@Expose
private String mobile;

/**
* 
* @return
* The home
*/
public String getHome() {
return home;
}

/**
* 
* @param home
* The home
*/
public void setHome(String home) {
this.home = home;
}

/**
* 
* @return
* The mobile
*/
public String getMobile() {
return mobile;
}

/**
* 
* @param mobile
* The mobile
*/
public void setMobile(String mobile) {
this.mobile = mobile;
}

}

然后你可以在你的 JsonResponse 中拨打电话

JSONObject phone=jsonObject.getJSONObject("phone");

String home=phone.getHome();

将返回您的家庭号码。

希望对你有帮助:)

Answer 3

也可以像这样直接从json对象中获取数据

if(JsonObject!=null){
String email=JsonObject.getString("email");
}  

或
为了让它工作在你的模型中编写getters()和setters()对象（人物对象），你也可以自动生成它。 一旦你这样做了，就会得到这样的数据

JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, APITEST,null, new Response.Listener<JSONObject>() {

        @Override
        public void onResponse(JSONObject jsonObject) {

            Gson gson = new Gson();
            People people;
            people = gson.fromJson(jsonObject.toString(),People.class);
            tv_city.setText(""+people.getEmail());

        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError volleyError) {



        }
    });

Answer 4

JSONObject phone=jsonObject.getJSONObject("phone");

String home=phone.getString("home");

现在您的家庭字符串中有家庭电话号码。