使用 Javascript 通过 JSON 查询类别答案

【问题标题】：Query category via JSON with Javascript使用 Javascript 通过 JSON 查询类别
【发布时间】：2021-01-26 23:37:03
【问题描述】：

我有这个 JSON 文件。我只想查询赛后类别，但我需要最后两个。

    {
    "videos" : [
        {
            "url" : "https://www.youtube.com/watch?v=DSorwgunfqo",
            "category" : "Pre-Game",
            "team" : ["Rodholfo Silva"],
            "date" : "January 20th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=qFzxV0Dc2rw",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 21st 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=nq0358cJb-M",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 17th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=iALl-ce5dzY",
            "category" : "Pre-Game",
            "team" : ["Rodholfo Silva"],
            "date" : "January 16th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=UY4WvV3dHNY",
            "category" : "Enterviews",
            "team" : ["Mathew Francis, Rodholfo Silva, Rod Patrón"],
            "date" : "July 16th 2020"
        },
        {
            "url" : "https://www.youtube.com/watch?v=7E2hMsmdbd4",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 24th 2021"
        }
    ]
}

我正在使用 Javascript，通过 for 循环和 slice(1).slice(-2)，但没有成功。

【问题讨论】：

标签： javascript json for-loop

【解决方案1】：

const data = [
        {
            "url" : "https://www.youtube.com/watch?v=DSorwgunfqo",
            "category" : "Pre-Game",
            "team" : ["Rodholfo Silva"],
            "date" : "January 20th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=qFzxV0Dc2rw",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 21st 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=nq0358cJb-M",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 17th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=iALl-ce5dzY",
            "category" : "Pre-Game",
            "team" : ["Rodholfo Silva"],
            "date" : "January 16th 2021"
        },
        {
            "url" : "https://www.youtube.com/watch?v=UY4WvV3dHNY",
            "category" : "Enterviews",
            "team" : ["Mathew Francis, Rodholfo Silva, Rod Patrón"],
            "date" : "July 16th 2020"
        },
        {
            "url" : "https://www.youtube.com/watch?v=7E2hMsmdbd4",
            "category" : "Post-Game",
            "team" : ["Rod Patrón"],
            "date" : "January 24th 2021"
        }
    ];

const postGames = data.filter(({ category }) => category === "Post-Game").slice(-2);
console.log(postGames);

/*

const postGames = data
    .filter(({ category }) => category === "Post-Game")
    .filter(({ date }) => //put your condition here)
    .slice(-2);
console.log(postGames);

const postGamesByDatet = data
    .filter(({category, date }) => category === "Post-Game" && date_is_after(date))
    .slice(-2);
*/

【讨论】：

太棒了。是否也可以“混合”过滤器并按日期对其进行排序？
如果您想在获取最后两项之前或slice 之后对结果进行排序，则可以在slice 之前通过将sort 函数链接到它来按日期对其进行排序最终结果，与过滤相同，如果您想按日期过滤所有 postGame，例如在 January 20th 之后，您只需将其添加到条件中。过滤器的“混合”是什么意思
混合我的意思是，就像添加多个过滤器。
是的，没有任何问题，您可以通过链接函数或在过滤器中添加新条件来堆叠函数，我已经更新了我的回复

【解决方案2】：

假设文件内容包含在records 变量中，而您想要的记录称为result：

const result = records.videos.filter(video => video.category === 'Post-Game').slice(-2);

【讨论】：

太棒了。是否也可以“混合”过滤器并按日期对其进行排序？