如何循环json数组以获取javascript中的键和值？答案

【问题标题】：How to loop json array to get key and value in javascript?如何循环json数组以获取javascript中的键和值？
【发布时间】：2016-03-28 08:54:23
【问题描述】：

我有下面的 json 数组结构.. 我怎样才能得到每个 records json 对象的键和值？

{
    "records": [{
        "cfsub_2": "1",
        "cf_7": "1/3/2016",
        "cf_1": "Clinic San",
        "cf_2": "Fever",
        "cf_3": "56.60",
        "cfe_8": "dsf4334"
    }, {
        "cfsub_2": "2",
        "cf_7": "3/3/2016",
        "cf_1": "Clinic Raju",
        "cf_2": "braces",
        "cf_3": "183.50",
        "cfe_8": "fresr4"
    }]
}

我的预期输出是获取键和值...以下示例：

<b>key</b> : cf_1, <b>value</b> : Clinic San

我尝试循环输入records，但由于我不知道key，所以无法获取值..

for (var z in records)
{
     var value = records[z].cf_1; 
     alert(value);
}

//i don't know the key here.. i want to get the key and value

完整的JSON结构如下：

{
"forms": [{
    "id": 1,
    "records": [{
        "cfsub_2": "1",
        "cf_7": "1/3/2016",
        "cf_1": "Clinic San",
        "cf_2": "Fever",
        "cf_3": "56.60",
        "cfe_8": "dsf4334"
    }, {
        "cfsub_2": "2",
        "cf_7": "3/3/2016",
        "cf_1": "Clinic Raju",
        "cf_2": "braces",
        "cf_3": "183.50",
        "cfe_8": "fresr4"
    }]
}, {
    "id": 7,
    "records": [{
        "cf_31": "27/3/2016",
        "cf_32": "Singapore",
        "cf_33": "dfd555",
        "cfe_34": ""
    }]
}, {
    "id": 11,
    "records": [{
        "cfsub_10": "9",
        "cf_9": "25/3/2016",
        "cf_10": "256.50",
        "cfe_11": "dfg44"
    }]
}]
}

【问题讨论】：

请说明您想要什么，您目前拥有什么，预期的输出是什么，以及您已经尝试解决什么问题。

标签： javascript json

【解决方案1】：

希望这篇文章对你有帮助。

$.each(value.forms, function(index,array){
    $.each(array.records, function(ind,items){
        $.each(items, function(indo,itemso){
            alert( "Key -> "+indo + " : values -> " + itemso );
        });
    });
});

【讨论】：

【解决方案2】：

var getKeys = function (arr) {
    var key, keys = [];
    for (i = 0; i < arr.length; i++) {
        for (key in arr[i]) {
            if (arr[i].hasOwnProperty(key)) {
                keys.push(key);
            }
        }
    }
    return keys;
};

【讨论】：