电子邮件错误帮助我解决语法错误

Question

import smtplib  
from email import encoders
from email.message import Message
from email.mime.audio import MIMEAudio
from email.mime.base import MIMEBase
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
msg = MIMEMultipart()
msg.attach(MIMEText(file("P:/Email/test.txt").read()))



sender = 'sender@email.com'  
reciever  = 'reciever@email.com'  
msg = 'Hello'  


# Credentials (if needed)  
username = 'user'  
password = 'pass'  

# The actual mail send  
server = smtplib.SMTP('localhost')  
server.starttls()  
server.login(username,password)  
server.sendmail(sender, reciever, msg)  
server.quit()  

回溯（最近一次调用最后一次）：文件“attach2.py”，第 27 行，在
server.sendmail(sender, reciever, msg) 文件“C:\Python33\lib\smtplib.py”，第 775 行，在 sendmail (code, resp) = self.data(msg) 文件“C:\Python33\lib\smtplib.py”，第 516 行，在 数据 q = _quote_periods(msg) 文件“C:\Python33\lib\smtplib.py”，第 167 行，在 quote_periods 返回 re.sub(br'(?m)^.', b'..', bindata) 文件 "C:\Python33\lib\re.py", 第 170 行，在 sub return _compile(pattern, flags).sub(repl, string, count) TypeError 中： 预期的字符串或缓冲区

为什么我会看到此错误消息。我的 python 库文件有问题吗？

Answer 1

上一行缺少右括号。

...
msg = MIMEMultipart()
msg.attach(MIMEText(file("P:/Email/test.txt").read())) # line missing a parenthesis

sender = 'whosends@something.com'
...

Answer 2

您的代码有 2 个错误。这是我的更正

import smtplib  
from email import encoders
from email.message import Message
from email.mime.audio import MIMEAudio
from email.mime.base import MIMEBase
from email.mime.image import MIMEImage
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
msg = MIMEMultipart()
msg.attach(MIMEText(file("P:/Email/test.txt").read()))



sender = 'sender@email.com'  
reciever  = 'reciever@email.com'  

# ***here don't overwrite the MIMEMultipart() obj***
# msg = 'Hello'  


# Credentials (if needed)  
username = 'user'  
password = 'pass'  

# The actual mail send  
server = smtplib.SMTP('localhost')  
server.starttls()  
server.login(username,password)

# ***here msg.as_string() to convert the MIMEMultipart() obj to a string***
server.sendmail(sender, reciever, msg.as_string())  

server.quit()  

Answer 3

这段代码运行良好

from email.mime.text import MIMEText

# ...

def send_mail(content):
    message = MIMEText(json.dumps(content))
    message["Subject"] = "Alert!"
    message["From"] = "alert@info.com"
    message["To"] = "abbas.kh@gmail.com"
    try:

        with smtplib.SMTP("smtp.mailtrap.io", 2525) as server:
            server.set_debuglevel(1)
            server.ehlo()  # Can be omitted
            server.ehlo()  # Can be omitted
            server.login("3247bc881dc002", "e6961e84f746ee")
            server.sendmail(message["From"] , message["To"], message.as_string())
        print('Sent')
    except smtplib.SMTPServerDisconnected:
        print('Failed to connect to the server. Wrong user/password?')
    except smtplib.SMTPException as e:
        print('SMTP error occurred: ' + str(e))
    except Exception as e:
        print('everything else')