【发布时间】:2021-02-21 10:06:55
【问题描述】:
我想找到一种方法,使用类似于 dplyr 包的东西在 Python 中从 R 重新创建相同的命令代码。在 R 中我会这样做:
library(dplyr)
df <- data.frame(Countries=c('Brazil','Venezuela','Brazil, Colombia, Paraguay','Argentina','Peru','Andorra,Argentina,Chile,Uruguay'),
Code=c(1,2,3,4,5,6))
df %>% filter(grepl('(Brazil|Argentina)',Countries))
甚至:
a=strsplit(as.character(df$Countries),',')
a=lapply(a,FUN=function(t) gsub(" ","",t))
ele=unlist(lapply(a,FUN=function(t) any(t%in%c('Brazil','Argentina'))))
(df[ele,])
我想要的输出:
Countries Code
1 Brazil 1
2 Brazil, Colombia, Paraguay 3
3 Argentina 4
4 Argentina,Chile,Uruguay 6
在 Python 中我试过这个:
import pandas as pd
df = pd.DataFrame(dict(Countries=['Brazil','Venezuela','Brazil, Colombia, Paraguay','Argentina','Peru','Andorra,Argentina,Chile,Uruguay'], Code=[1,2,3,4,5,6]))
list_=['Brazil','Argentina']
print(df.loc[df['Countries'].isin(list_)])
但输出看起来像:
Countries Code
0 Brazil 1
3 Argentina 4
【问题讨论】: