更新:添加了可以在需要 OUTER 连接时使用的 Linq 表达式。
内连接
对于内部连接,即。只取回至少购买过一次的物品,可以使用以下。
LINQ 2 SQL
from a in Articles
join c in CustomersRecords on
a.Article_Name equals c.Article_Name
group a by new {a.SNo, a.Article_Name} into g
select new
{
SNo = g.Key.SNo,
Article_Name = g.Key.Article_Name,
Total_Items_Bought = g.Count()
}
上面的转换成下面的SQL
SELECT COUNT(*) AS [Total_Items_Bought], [t0].[SNo], [t0].[Article_Name]
FROM [Articles] AS [t0]
INNER JOIN [CustomersRecord] AS [t1] ON [t0].[Article_Name] = [t1].[Article_Name]
GROUP BY [t0].[SNo], [t0].[Article_Name]
稍微清理一下就会给你
SELECT a.SNo,
a.Article_Name,
COUNT(*) AS Total_Items_Bought
FROM Articles AS a
INNER JOIN CustomersRecord AS c ON a.Article_Name = c.Article_Name
GROUP BY a.SNo, a.Article_Name
左外连接
对于左外连接,即。取回所有未购买的文章事件,您可以使用以下。
LINQ 2 SQL
from a in Articles
join c in CustomersRecords on
a.Article_Name equals c.Article_Name into apc
select new
{
SNo = a.SNo,
Article_Name = a.Article_Name,
Total_Items_Bought = apc.Count()
}
这将转换为以下 SQL
SELECT [t0].[SNo], [t0].[Article_Name], (
SELECT COUNT(*)
FROM [CustomersRecord] AS [t1]
WHERE [t0].[Article_Name] = [t1].[Article_Name]
) AS [Total_Items_Bought]
FROM [Articles] AS [t0]