如果第 5 个元素是“名称”，则按每第 4 个元素拆分列表；如果第 5 个元素是地址，则按第 5 个元素拆分

Question

我有一个 8000 个名称列表，其中包含按如下所示顺序排列的名称、公司、地址 1、地址 2、地址 3（可选）。这是一个python列表

[John
It Tech
1243 mary drive
florida-32006
mark
Infotech
1245 lonely drive
irony estate 324
Virginia-24531
Steve
king Electronics
.
.
]

address3 是可选的，不能期望它每次都按顺序排列。name 将从 address2 的下一个开始。我需要按每个第 n 个元素拆分列表，即通过名称检查第 5 个元素是名称或地址。如果是地址，则将拆分增加 nth+1。如果没有，继续 4。我只是想将这些添加到 excel 列中。

下面是我尝试过的代码，它按每 4 个元素拆分列表。如果第 5 个元素是名称或地址，它会忽略。

test2= [final1[x:x+4] for x in range(0, len(final1),4)]

这给了我结果

[['John','It Tech','1243 mary drive','florida-32006'], 
['mark','Infotech','1245 lonely drive','irony estate 324'],
['Virginia-24531','Steve','king Electronics']] 
** the last list should start from Steve and the address(Virginia-24531) in the previous list***

我恳请有人帮我解决这个问题。提前非常感谢你

Answer 1

下面的假设是地址有连字符而名称没有（非常危险）。然后它会根据最后一个条目 [-1] 是地址还是名称来剪切列表的前 4 个或 5 个元素。

result=[]
for x in range(len(final1)):
    tmp = final1[:5] if len(final1) >= 5 else final1
    if len(tmp)==0:
        break

    if '-' in tmp[-1]:
        result.append(tmp) 
        final1 = final1[5:]
    else:
        result.append(final1[:4])
        final1 = final1[4:]
result

[['John', 'It Tech', '1243 mary drive', 'florida-32006'],
 ['mark','Infotech','1245 lonely drive','irony estate 324','Virginia-24531'],
 ['Steve', 'king Electronics']]

Answer 2

您的地址似乎包含数字 - 您的 姓名* 没有。您可以使用它进行相应的拆分：

from string import digits

def splitIt(data):
    i = 0
    tmp = []
    for d in data:
        # the first 4 lines we add without check - datasets have always 4 lines minimum
        if i > 3:            # this will break if you have data with fewer then 4 lines
            if not any(c in digits for c in d):  # if the 5th line has no numbers: NAME
                yield tmp
                tmp = [d]
                i = 1
        else:                                    # else another address line, check 6th
            tmp.append(d)                        # line for name (you can have as many 
            i += 1                               # lines with numbers in it after the 4th)
    yield tmp


data = ["John",       # no number
"It Tech",
"1243 mary drive",    # has number
"florida-32006",      # has number
"mark",               # no number
"Infotech",
"1245 lonely drive",
"irony estate 324",
"Virginia-24531",
"Steve",
"king Electronics",]

print(list(splitIt(data)))

输出：

[['John', 'It Tech', '1243 mary drive', 'florida-32006'], 
 ['mark', 'Infotech', '1245 lonely drive', 'irony estate 324'], 
 ['Steve', 'king Electronics']]

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免责声明：Falsehoods Programmers Believe About Names