Python - 在熊猫数据框中对列表中的行进行分组

Question

我有一个这样的数据框：

long lat Place
-6.779 61.9 奥胡斯
-6.790 62.0 奥胡斯
54.377 24.4 扎比
38.834 9.0 亚的斯
35.698 9.2 亚的斯

    Is it possible to transform the dataframe into a format like below?

Office    long + lat
Aarhus     [[-6.779,61.9], [-6.790,62.0]]
Dhabi      [[54.377]]
Addis      [[38.834,9.0], [35.698,9.2]]

我尝试了不同的方法，但仍然无法解决这个问题。这是 我试图为每个不同的位置值获取一个列表：

df2["index"] = df2.index
df2["long"]=df2.groupby('index')['long'].apply(list)
list 1= [] 
for values in ofce_list:
    if df['Office'].any() == values:
        list1.append(df.loc[df['Office'] == values, 'long'])

    But this returned a series in a list instead which is not desired. Please help. Thank you so much.

Answer 1

 df.groupby('Place')[['long','lat']].apply(lambda x :x.values.tolist()).\
      reset_index(name='long + lat')
Out[1380]: 
    Place                       long + lat
0  Aarhus  [[-6.779, 61.9], [-6.79, 62.0]]
1   Addis   [[38.834, 9.0], [35.698, 9.2]]
2   Dhabi     [[54.376999999999995, 24.4]]