【发布时间】:2017-03-21 15:49:37
【问题描述】:
在下面的代码中创建了一个示例treegrid jqGrid,图像显示了生成的网格:
代码如下:
<!DOCTYPE html>
<html>
<head lang="en">
<meta charset="UTF-8">
<title></title>
<link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.css">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/font-awesome/4.5.0/css/font-awesome.css">
<link rel="stylesheet" href="https://rawgit.com/free-jqgrid/jqGrid/master/css/ui.jqgrid.css">
<style>
.ui-jqgrid.ui-jqgrid-bootstrap .ui-jqgrid-hdiv {
background-color: #ffaaaa;
}
.ui-jqgrid.ui-jqgrid-bootstrap .ui-jqgrid-toppager,
.ui-jqgrid.ui-jqgrid-bootstrap .ui-jqgrid-pager {
background-color: #ffaaaa;
}
</style>
</head>
<body>
<table id="list10"></table>
<div id="pager"></div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.4/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/bootstrap-datepicker/1.5.1/js/bootstrap-datepicker.js"></script>
<script>
$.jgrid = $.jgrid || {};
$.jgrid.no_legacy_api = true;
$.jgrid.useJSON = true;
</script>
<script src="https://rawgit.com/free-jqgrid/jqGrid/master/js/jquery.jqgrid.src.js"></script>
<script type="text/javascript">
$(function(){
var mydata = [
{id:"1",Name:"Main Menu",MenuId:"1",MenuName:"Menu1",
level:"0", parent:"", isLeaf:false, expanded:false},
{id:"1_1",Name:"Sub Menu",MenuId:"1",MenuName:"Menu1",
level:"1", parent:"1", isLeaf:false, expanded:false},
{id:"1_1_1",Name:"Sub Sub Menu",MenuId:"1",MenuName:"Menu1",
level:"2", parent:"1_1", isLeaf:true, expanded:false},
{id:"1_2",Name:"Sub Menu1",MenuId:"1",MenuName:"Menu1",
level:"1", parent:"1", isLeaf:true, expanded:false},
{id:"2",Name:"Main Menu1",MenuId:"2",MenuName:"Menu2",
level:"0", parent:"", isLeaf:false, expanded:true},
{id:"2_1",Name:"Main Menu sdaadadadadadaadsdada",MenuId:"2",MenuName:"Menu2",
level:"1", parent:"2", isLeaf:true, expanded:false},
{id:"2_2",Name:"Main Menu",MenuId:"2",MenuName:"Menu2",
level:"1", parent:"2", isLeaf:true, expanded:false},
{id:"3",Name:"Main Menu2",MenuId:"3",MenuName:"Menu3",
level:"0", parent:"", isLeaf:false, expanded:false},
{id:"3_1",Name:"Main Menu",MenuId:"3",MenuName:"Menu3",
level:"1", parent:"3", isLeaf:true, expanded:false},
{id:"3_2",Name:"Main Menu",MenuId:"3",MenuName:"Menu3",
level:"1", parent:"3", isLeaf:true, expanded:false}
];
$("#list10").jqGrid({
datatype: "local",
data: mydata,
colNames:['id','Name','MenuId','Menu Name'],
colModel:[
{name:'id',index:'id',width:100,hidden:true},
{name:'Name',index:'Name',width:150},
{name:'MenuId',index:'MenuId',width:100},
{name:'MenuName',index:'MenuName',width:100}
],
cmTemplate: { autoResizable: true, editable: true },
autoResizing: { compact: true },
iconSet: "fontAwesome",
guiStyle: "bootstrap",
height:'auto',
pager : "pager",
sortname: 'id',
treeGrid: true,
treeGridModel: 'adjacency',
treedatatype: "local",
ExpandColumn: 'Name',
caption: "Sample Tree View Model"
});
})
</script>
</body>
</html>
我想知道做以下事情:
如您所见,叶子 Main Menu sdaadadadadadaadsdada 对于叶子来说确实很长。我如何包装它以使用户可以看到文本而不扩展列,同时文本必须与单选按钮(项目符号)图标保持对齐。
如何更改顶部标题栏的背景和文字颜色?
如何将树节点(箭头)和叶子(项目符号/单选按钮图标)的默认图标图像更改为加/减(对于父节点)图标和暗点(对于叶子)?
当我单击当前显示绿色的行时,如何将其更改为另一种颜色?
当我将鼠标悬停在以灰色突出显示的行上时,我如何也更改此颜色?
【问题讨论】:
-
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标签: jqgrid free-jqgrid