jqgrid 搜索弹出窗口允许删除所有过滤器！答案

【问题标题】：jqgrid search popup allows all filters to be removed!jqgrid 搜索弹出窗口允许删除所有过滤器！
【发布时间】：2011-05-19 20:03:21
【问题描述】：

我正在 JqGrid 上尝试非常简单的搜索弹出窗口。请看下面的代码。有几个问题：

弹出窗口的顶部带有 AND/OR 和 [+] 控件。请看下面的截图：（来自 FF 4）
您可以单击 [-] 按钮删除第一个（也是唯一一个）过滤器行。它不应该被允许。绝不应允许删除第一个过滤器行。

代码：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
 <html>
<head>
<title>JQGRID Test</title>      
<link rel="stylesheet" type="text/css" media="screen" href="http://trirand.com/blog/jqgrid/themes/redmond/jquery-ui-1.8.1.custom.css"/>
<link rel="stylesheet" type="text/css" media="screen" href="http://trirand.com/blog/jqgrid/themes/ui.jqgrid.css"/>

<script type="text/javascript" src="http://trirand.com/blog/jqgrid/js/jquery.js"></script>
<script type="text/javascript" src="http://trirand.com/blog/jqgrid/js/jquery-ui-1.8.1.custom.min.js"></script>
<script type="text/javascript" src="http://trirand.com/blog/jqgrid/js/i18n/grid.locale-en.js"></script>
<script type="text/javascript" src="http://trirand.com/blog/jqgrid/js/jquery.jqGrid.min.js"></script>

<script type="text/javascript">
    $(function() {
        createGrid();
    });
    function createGrid() {
        $("#jqgrid-table").jqGrid({
            colNames:['First Name', 'Last Name', 'Age', 'IQ', 'Type'],
            colModel:[
                {name:'firstName',index:'firstName', width:100},
                {name:'lastName',index:'lastName', width:100},
                {name:'age', index:'age', width:50},
                {name:'iq', index:'iq', width:50, stype:'select', searchoptions: {dataUrl:'/api/domains/putcalldomain'}},
                {name:'type', index:'type', width: 56}
            ],
            width: 800,
            datatype:'local',                   
            pager: '#pager2',
            viewrecords: true,
            caption:"JSON Example"
        });
        var searchOptions = {
            caption: 'Filter...',
            multipleSearch:true,
            closeAfterSearch:true,
            closeAfterReset:true,
            Find: 'Filter'
        };                
        jQuery("#jqgrid-table").jqGrid('navGrid',
                                '#pager2', 
                                {search:true, edit:false, add:false, del:false, refresh:false}, 
                                null, null, null, searchOptions
                                );
        var data = getData();
        for(var i =0; i < data.length; i++) {
            var r = data[i];
            jQuery("#jqgrid-table").addRowData(r.id, r);
        }
    }
    function getData() {
        return [
               {id:1, firstName: 'John', lastName: 'XXX',  age:'30',  iq:'200', type: 'Nice'},
               {id:2, firstName: 'Ashley', lastName:'YYY', age:'31', iq:'210', type:'Nicer'},
               {id:3, firstName:'Smith', lastName:'ZZZ', age:'23', iq:'90', type:'Nicest'}
            ];
   }

</script>
</head>
<body>
  <div id='jqgrid-div'>
      <table id='jqgrid-table'></table>
     <div id="pager2"></div>
  </div>
</body>
</html>

【问题讨论】：

标签： jqgrid

【解决方案1】：

我建议覆盖过滤使用的内部reDraw 方法（有关详细说明，请参阅my another answer）。为此，您应该在searchOptions 中包含您使用beforeShowSearch 事件处理程序的以下实现：

beforeShowSearch: function($form) {
    var searchDialog = $form[0],
        oldrReDraw = searchDialog.reDraw, // save the original reDraw method
        doWhatWeNeed = function() {
            $('input.delete-rule:first',searchDialog).unbind('click');

            // set fucus in the last input field
            setTimeout(function() {
               // set fucus in the last input field
               $('input[type="text"]:last',searchDialog).focus();
            }, 50);
        }
    searchDialog.reDraw = function() {
        oldrReDraw.call(searchDialog);    // call the original reDraw method
        doWhatWeNeed();
    }
    doWhatWeNeed();
}

可以看对应的demohere。

【讨论】：