【发布时间】：2011-11-14 14:47:25
【问题描述】：
Json 数据为：
{id: "1", name: "Cash", num: "100", debit: "400.00", credit: "250.00",
balance: "150.00", enbl: "1", level: "0", parent: "null",
isLeaf: false, expanded: true, loaded: true}
参数“expanded”好像没用？
我的json数据初始化时不知道如何展开所有节点或某个指定节点？
致 Oleg：感谢您的演示，但我无法访问该页面！ - -！ 然后，我给你看我的javascript代码，也许你会发现一些问题：
$(function () {
$('#list').jqGrid({
url: 'SvcDept.ashx',
ajaxGridOptions: { contentType: 'application/json; charset=utf-8' },
datatype: 'json',
mtype: 'GET',
treeGrid: true,
treeGridModel: 'adjacency',
ExpandColumn: 'Name',
colNames: ['ID', 'Name', 'Director', 'ParentID'],
colModel: [
{ name: 'ID', index: 'ID', hidden: true, width: 1, key: true },
{ name: 'Name', index: 'Name', width: 200, fixed: true },
{ name: 'Director', index: 'Director', width: 100 },
{ name: 'ParentID', index: 'ParentID', hidden: true, width: 1 }
],
autowidth: true,
height: 'auto'
});
});
和我的 SvcDept.ashx：
public class SvcDept
{
public void ProcessRequest(HttpContext context)
{
var depts = context.Application["Departments"] as List<Department>;
var nodeid = context.Request["nodeid"];
var n_level = context.Request["n_level"];
Guid? deptID = nodeid != null ? new Guid(nodeid) : new Nullable<Guid>();
int level = n_level != null ? int.Parse(n_level) + 1 : 0;
var subDepts = depts.Where<Department>(x => x.ParentID == deptID).ToList<Department>();
var data = new
{
page = 1,
total = 1,
records = subDepts.Count,
rows = (from dept in subDepts
select new
{
cell = new[]
{
dept.ID.ToString(),
dept.Name,
dept.Director ,
dept.ParentID != null ? dept.ParentID.ToString() : "",
level.ToString(), //Level
deptID != null ? deptID.ToString() : "null", //ParentID
depts.Count<Department>(x => x.ParentID == dept.ID) == 0 ? "true":"false", //isLeaf
"true", //expanded
"false"//loaded
}
})
};
context.Response.ContentType = "application/json";
JavaScriptSerializer serializer = new JavaScriptSerializer();
context.Response.Write(serializer.Serialize(data));
}
public bool IsReusable
{
get
{
return false;
}
}
}
public class Department
{
public Guid ID { get; set; }
public string Name { get; set; }
public string Director { get; set; }
public Guid? ParentID { get; set; }
}
【问题讨论】：
标签： javascript jquery json jqgrid treegrid