猜谜游戏 - 随机 #1 到 100，要求用户 5 次猜测正确数字.....BEGINNER JAVA

Question

设计一个应用程序，从 1 到 100 中选择一个随机数，然后提示用户猜测该数字，警告用户他们只剩下 5 次尝试才能正确猜测。每次猜测后，向用户报告他或她是正确的还是猜测太高或太低。如果猜对了，打印出祝贺信息。如果猜 5 次不成功，则打印一条消息说游戏结束。在游戏结束时，提示用户表明他/她是否希望再次玩游戏。

我特别需要关于结尾的帮助，我猜还有代码的布局......我运行它并且它不断运行，我尝试使用几个网站和我的教科书但没有运气，提前谢谢你！ ！

Java、Net beans 8.2

import java.util.Random;
import java.util.Scanner;

public class GuessingGame 
{
    public static void main (String[]args)
    {
        int answer, guess,attemptsNum = 0;
        final int maxAttempts = 5;
        String str, another = "y";

        Scanner scan = new Scanner(System.in);
        Random generator = new Random();
        answer = generator.nextInt(101)+1;

        System.out.println("Guess a number between 1 and 100");
        System.out.println("Enter your guess (0 to quit):");

        {
            guess = scan.nextInt();
            while (guess != 0)
            {
                if(guess==answer)
                        System.out.println("Right!");
                else if (guess<answer)
                    System.out.println("Your guess was too LOW.");
                else if (guess>answer)
                    System.out.println("Your guess was too HIGH.");
            }

            System.out.println("Want to Play again?(y/n)");
            another = scan.next();

            while (guess != answer && ++attemptsNum < maxAttempts)
                if (attemptsNum == maxAttempts)
                    System.out.println ("The number was " + answer);
    }
}

}

输入您的猜测（0 表示退出）：20 你的猜测太低了

输入您的猜测（0 表示退出）：35 你的猜测太低了

输入您的猜测（0 表示退出）：80 你的猜测太高了

输入您的猜测（0 表示退出）：74 你的猜测太高了

输入您的猜测（0 表示退出）：56 对！猜测：5

再玩一次（是/否）？

Answer 1

几个cmets：

1. 您需要对代码进行格式化。这使它更具可读性。
2. 您的生成器生成一个介于 1 和 101 之间的值。它应该只是 answer = generator.nextInt(100)+1;
3. 你的循环和你的一些逻辑是错误的
4. 我建议始终在public static void main 之外创建一个单独的方法。这是常见的做法，这也允许您再次调用它自己的方法。

这就是我的解决方法：

import java.util.Random; import java.util.Scanner;

class Main {
  public static Scanner scan = new Scanner(System.in);

  public static void main (String[]args) {
    runGame();
  }

  public static void runGame() {
    String another = "";
    int answer, guess,attemptsNum = 0;
    final int maxAttempts = 5;

    Random generator = new Random();
    answer = generator.nextInt(100)+1;

    System.out.println("Guess a number between 1 and 100");
    System.out.println("Enter your guess (0 to quit):");

    guess = scan.nextInt();
    while (guess != answer && attemptsNum < maxAttempts-1 && guess != 0 ) {
      if(guess==answer)
            System.out.println("Right!");
      else if (guess<answer) {
        System.out.println("Your guess was too LOW.");
        attemptsNum++;
        guess = scan.nextInt();
      } 
      else {
        System.out.println("Your guess was too HIGH.");
        attemptsNum++;
        guess = scan.nextInt();
      }
    }

    System.out.println ("The number was " + answer);
    System.out.println("Want to Play again?(y/n)");
    another = scan.next();
    System.out.println("another = " + another);
    if(another.equals("y")) {
      runGame();
    } else {
      System.out.println("Goodbye!");
    }
  }
}

但无论哪种方式，只要继续练习。你会得到它的窍门！

Answer 2

我看到外部 while 循环需要重新构建，并且一些逻辑错位了。试试修改后的版本，希望对你有帮助。如果您有任何问题，请评论我。

import java.util.Random;
import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int answer, guess, attemptsNum = 0;
        final int maxAttempts = 5;
        String str, another = "y";

        Scanner scan = new Scanner(System.in);
        Random generator = new Random();
        answer = generator.nextInt(101) + 1;

        while (another.equals("y") || another.equals("Y")) {
            System.out.println("Guess a number between 1 and 100");

            System.out.println("Enter your guess (0 to quit):");

            guess = scan.nextInt();
            attemptsNum = 0;
            while (guess != 0)

            {
                attemptsNum++;
                if (guess == answer) {
                    System.out.println("Right!");
                    break;
                } else if (guess < answer)
                    System.out.println("Your guess was too LOW.");
                else if (guess > answer)
                    System.out.println("Your guess was too HIGH.");

                if (attemptsNum == maxAttempts) {
                    System.out.println("The number was " + answer);
                    break;

                }

                System.out.println("Enter your guess (0 to quit):");
                guess = scan.nextInt();
            }

            System.out.println("Want to Play again?(y/n)");
            another = scan.next();
        }
        System.out.println("Thanks for playing");
    }
}

Answer 3

我可以看到 javapedia.net 已经先回答了，但我已经独立提出了这个答案。为了便于阅读，我添加了括号。对于猜测太高或太低的 if 语句添加了尝试数++。

import java.util.Random;
import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int answer, guess, attemptsNum = 0;
        final int maxAttempts = 5;
        String str, another = "y";

        Scanner scan = new Scanner(System.in);
        Random generator = new Random();
        answer = generator.nextInt(101) + 1;

        System.out.println("Guess a number between 1 and 100");
        System.out.println("Enter your guess (0 to quit):");

        guess = scan.nextInt();
        while (guess != 0) {
            if (guess == answer) {
                System.out.println("Right!");
                guess = 0;
            } else if (guess < answer) {
                System.out.println("Your guess was too LOW.");
                attemptsNum++;
                guess = scan.nextInt();
            } else {
                System.out.println("Your guess was too HIGH.");
                attemptsNum++;
                guess = scan.nextInt();
            }
            if (attemptsNum >= (maxAttempts-1)) {
                System.out.println("The number was " + answer);
            }
        }
    }
}