【发布时间】:2013-11-08 04:28:38
【问题描述】:
我需要在 UIWebView 中创建多个按钮。所以,我使用标签作为按钮。我使用 INTEGER 将按钮标签保存到数据库中。但这并没有节省适当的价值。每个按钮标签在数据库中都有文本。稍后我需要检索。但是在将最后一个值存储到数据库并单击任何其他按钮后,它只会获取最后一个更新的值。为什么会这样?
表:
textnotes text_id button_id
hi 1 1
how are you 1 3
im fine 2 7
This is test 2 11
UI按钮:
int gTag = 1;
webviewbutton.tag = gTag;
gTag++;
[wbCont.scrollView addSubview:webviewbutton];
插入:
const char *sqlInsert = [[NSString stringWithFormat:@"insert into textnote (textnotes,text_id,button_id ) values ('%@','%@','%ld')", txtview.text,artID,(long)webviewbutton.tag] cStringUsingEncoding:NSUTF8StringEncoding];
从数据库中检索带有文本的按钮标签:
textArray=[[NSMutableArray alloc]init];
webbutton_art=[[NSMutableArray alloc]init];
webbutton_button=[[NSMutableArray alloc]init];
if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) {
const char *sql = [[NSString stringWithFormat:
@"SELECT textnotes,text_id,button_id FROM textnote where button_id = '%ld' AND text_id = '%@' ",(long)webviewbutton.tag,artID]cStringUsingEncoding:NSUTF8StringEncoding];
NSLog(@"sql is %s",sql);
sqlite3_stmt *statement;
if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
while (sqlite3_step(statement) == SQLITE_ROW) {
txtstring = [[NSString alloc] initWithUTF8String:
(const char *) sqlite3_column_text(statement, 0)];
webbutton_textartid = sqlite3_column_int(statement, 1);
webbutton_buttontag= sqlite3_column_int(statement, 2);
[textArray addObject:txtstring];
[webbutton_art addObject:@(webbutton_textartid)];
[webbutton_button addObject:@(webbutton_buttontag)];
if( webbutton_art && webbutton_button ){
for(int i=0;i<[textArray count];i++){
txtview = [[UITextView alloc]initWithFrame:CGRectMake(0,0,320,568)];
txtview.font = [UIFont fontWithName:@"Helvetica" size:12];
txtview.text=[textArray objectAtIndex:i];
[self.view addSubview:txtview];
}
}
【问题讨论】:
-
第一件事是再次检查标签
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我没有得到。如何?我需要在检索中更改代码吗?
-
记录它们以查看您使用断点检查的值,标准,我认为它缺少一个小东西,只有彻底审查才会陶醉
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int gTag = 1; 我希望你每次都在初始化,它不会递增......
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or(int i=0;i
标签: ios sqlite tags uibutton nsmutablearray