如何删除标签之间的值？

Question

我想删除标签内的值，我该怎么做？当我加载保存文件时，突出显示的输出是我想要删除的内容。

 <data name="Enrolment_Exit_Verify_Message" d2p1:space="preserve"  xmlns:d2p1="http://www.w3.org/XML/1998/namespace">
<value**>**Are you sure you want to Exit without Saving?****</value>
<comment>[Font]**Italic**[/Font][DateStamp]2015/02/01 00:00:00[/DateStamp][Comment] **this is a My awesome new comments comment.!!**[/Comment]</comment>

这是我在标签之间的阅读方式？我不知道如何删除标签之间的内容。

            for (int i = 0; i < oDataSet.Tables[2].Rows.Count; i++)
            {
                string comment = oDataSet.Tables["data"].Rows[i][2].ToString();

                string font = Between(comment, "[Font]", "[/Font]");
                string datestamp = Between(comment, "[DateStamp]", "[/DateStamp]");
                string commentVal = Between(comment, "[Comment]", "[/Comment]");

                string[] row = new string[] 
                {
                    oDataSet.Tables["data"].Rows[i][0].ToString(),
                    oDataSet.Tables["data"].Rows[i][1].ToString(),
                    font, 
                    datestamp, commentVal };
                Gridview_Output.Rows.Add(row);
            }
            oDataSet.Tables.Add(oDataTable);

字符串函数

    public string Between(string STR, string FirstString, string LastString)
    {
        string FinalString;
        int Pos1 = STR.IndexOf(FirstString) + FirstString.Length;
        int Pos2 = STR.IndexOf(LastString);
        FinalString = STR.Substring(Pos1, Pos2 - Pos1);
        return FinalString;
    }

Answer 1

如果您可以构建正则表达式，您可以在 between 方法中使用正则表达式。 Here is more info on the regex

     public string Between(string STR, string FirstString, string LastString)
     {
         string regularExpressionPattern1 = @"(?:\" + FirstString + @")([^[]+)\[\/" + LastString;
        Regex regex = new Regex(regularExpressionPattern1, RegexOptions.Singleline);
        MatchCollection collection = regex.Matches(STR.ToString());
        var val = string.Empty;
        foreach (Match m in collection)
        {
            val = m.Groups[1].Value;
        }
        return val;
     }

注意- 未经测试的代码可能需要根据您的需要进行调整。 Althoguh 正则表达式经过测试。

Here is working fiddle for regex

在执行函数后，上面的代码为您提供了标签中的值，变量将具有值

   font = "**Italic**"  
   datestamp = "2015/02/01 00:00:00"
   commentVal = "**this is a My awesome new comments comment.!!**"

如果你想从comment 变量中删除它，只需使用Replaceas

  comment = comment.Replace(font,string.Empty);
  comment = comment.Replace(datestamp ,string.Empty);
  comment = comment.Replace(commentVal ,string.Empty);

最后，您将拥有 comment 变量，其中已从该标签中删除了值。

Answer 2

要删除中间的值，可以修改Code的@Coder提供的正则表达式，如下所示：

        string str = "[Font]**Italic**[/Font][DateStamp]2015/02/01 00:00:00[/DateStamp][Comment] **this is a My awesome new comments comment.!!**[/Comment]";
        string strPattern = @"(?:])([^[]+)\["; // Regular expression pattern to find string inside ][
        Regex rg = new Regex(strPattern);
        string newStr = rg.Replace(str, string.Format("]{0}[",string.Empty), int.MaxValue);