“标记“else”的语法错误，删除此标记”（Java）答案

【问题标题】："Syntax error on token "else", delete this token" (Java)“标记“else”的语法错误，删除此标记”（Java）
【发布时间】：2021-02-02 17:25:02
【问题描述】：

所以我在第 37 行遇到了 else if 错误，我不知道为什么会这样。 IDE 说：“令牌“else”上的语法错误，删除此令牌”。谢谢。

package jogo;

import java.util.Scanner;
import java.util.Random;

public class Main 
{
    public static void main(String[] args)
    {   
     Scanner in = new Scanner(System.in);
     Random rand = new Random();
     String name;
     System.out.println("Welcome to the game! Enter your name.");
     name = in.nextLine();
     System.out.println("Welcome " +name);
     System.out.println("Which direction you will walk? ( W, A, S D )");
     String comando = in.nextLine();
     
     if(comando.equals("W"));
        System.out.println("You decided to walk through the vast forest.");
        System.out.println("And suddenly a goblin appeared, what are you going to do? ( A = Attack and C = Run )");
        comando = in.nextLine();
        if(comando.equals("A"));
            if(rand.nextInt(100) <= 75)
        {
            System.out.println("You won the battle.");
        }
        else
        {
            System.out.println("You lost the battle.");
            {       
            else if(comando.equals("C")); 
            System.out.println("You ran away from the battle.");
            }   
        }
    }
}

【问题讨论】：

您的if 结构非常损坏，再加上不一致的缩进，我不知道哪个else 与哪个if 搭配使用。从if 语句中删除分号，一致地将if 和else 代码块包裹在花括号中，并使用一致的缩进。目前你和编译器读取代码的方式不同，这会导致你的困惑。
很难从你的代码中推断出你想要做什么。编译错误是由于else if(comando.equals("C")); 行引起的。 else if 在没有任何“如果”的情况下存在。尽管修复此问题将导致编译成功，但似乎存在一些逻辑错误。例如：if(comando.equals("A"));，在 if 语句之后放置一个分号没有任何作用。

标签： java if-statement

【解决方案1】：

在您的程序中，if、else if 和 else 的语法不正确。这是您使用正确语法的代码。

    Scanner in = new Scanner(System.in);
    Random rand = new Random();
    String name;
    System.out.println("Welcome to the game! Enter your name.");
    name = in.nextLine();
    System.out.println("Welcome " +name);
    System.out.println("Which direction you will walk? ( W, A, S D )");
    String comando = in.nextLine();
 
    if(comando.equals("W")){
        System.out.println("You decided to walk through the vast forest.");
        System.out.println("And suddenly a goblin appeared, what are you going to do? ( A = Attack and C = Run )");
        comando = in.nextLine();
        if(comando.equals("A")){
            if(rand.nextInt(100) <= 75){
                System.out.println("You won the battle.");
            }else{
                System.out.println("You lost the battle.");
            }
        }
        else if(comando.equals("C")){
            System.out.println("You ran away from the battle.");
        }
    }

同时检查Java Conditions and If Statements

【讨论】：

【解决方案2】：

代码中几乎没有错误，例如在某些 if 条件后您放置了分号 (;) ，甚至还有一些括号错误。我已经编辑了代码，现在它可以正常工作了。

package jogo;

import java.util.Scanner;
import java.util.Random;

public class Main 
{
    public static void main(String[] args)
    {
    Scanner in = new Scanner(System.in);
    Random rand = new Random();
    String name;
    System.out.println("Welcome to the game! Enter your name.");
    name = in.nextLine();
    System.out.println("Welcome " +name);
    System.out.println("Which direction you will walk? ( W, A, S D )");
    String comando = in.nextLine();
    
    if (comando.equals("W")){
        System.out.println("You decided to walk through the vast forest.");
        System.out.println("And suddenly a goblin appeared, what are you going to do? ( A = Attack and C = Run )");
        comando = in.nextLine();
        
        if(comando.equals("A")){
            if(rand.nextInt(100) <= 75){
            System.out.println("You won the battle.");
        }
            else{
                System.out.println("You lost the battle.");
            }
        
        }
        
        else if(comando.equals("C")){
            System.out.println("You ran away from battle");
        }
    }
        
    }
    
}

【讨论】：