使用 spring mongotemplate 进行条件查询

Question

我想使用条件查询。

这是我的查询

db.projects.aggregate([
{
    "$group": {
        "_id": "$iecode",
        "treatmentArms": { "$first": "$evaluationDTOList" }
    }
},
{ "$unwind": "$treatmentArms" },
{
    "$group": {
        "_id": null,
        "Package": { 
            "$sum": { 
               "$cond": [ 
                   { "$eq": [ "$treatmentArms.mechanismOrPkg", "Package" ] }, 
                   1, 0
                ] 
            }
        },
        "Constraint-relaxing mechanisms": { 
            "$sum": { 
               "$cond": [ 
                    { 
                        "$and": [
                            { "$eq": [ "$treatmentArms.mechanismOrPkg", "Mechanism" ] },
                            { "$eq": [ "$treatmentArms.mechanismTested1", "Constraint-relaxing mechanisms" ] }
                        ]
                    }, 
                    1, 
                    0 ]
            }
        },
        "Delivery mechanisms": { 
            "$sum": { 
               "$cond": [ 
                    { 
                        "$and": [
                            { "$eq": [ "$treatmentArms.mechanismOrPkg", "Mechanism" ] },
                            { "$eq": [ "$treatmentArms.mechanismTested1", "Delivery mechanisms" ] }
                        ]
                    }, 
                    1, 
                    0 ]
            }
        },
        "Other": { 
            "$sum": { 
               "$cond": [ 
                    { 
                        "$and": [
                            { "$eq": [ "$treatmentArms.mechanismOrPkg", "Mechanism" ] },
                            { "$eq": [ "$treatmentArms.mechanismTested1", "Other" ] }
                        ]
                    }, 
                    1, 
                    0 ]
            }
        }
    }
}
])

这是我的java代码

DBObject groupByIECode = new BasicDBObject("$group",
                new BasicDBObject("_id", new BasicDBObject("iecode","$iecode")).append("treatmentArms",new BasicDBObject("$first","$evaluationDTOList")));
        System.out.println("groupByIECode: "+groupByIECode.toString());

        DBObject unwind = new BasicDBObject("$unwind","$treatmentArms");
        System.out.println("unwind: "+unwind.toString());


        DBObject finalCalculation = new BasicDBObject("$group",new BasicDBObject("_id",null))
                                    .append(
                                            "Package", new BasicDBObject(
                                                "$sum", new BasicDBObject(
                                                    "$cond", new Object[]{
                                                        new BasicDBObject(
                                                            "$eq", new Object[]{ "$treatmentArms.mechanismOrPkg", "Package"}
                                                        ),
                                                        1,
                                                        0
                                                    }
                                                )
                                            )
                                        );

        System.out.println("finalCalculation: "+finalCalculation);
        final AggregationOutput output = projects.aggregate(match,groupByIECode,unwind,finalCalculation);

它给了我MongoException$DuplicateKey

后来发现spring mongotemplate不支持$cond操作符。那么如何使用spring mongotemplate 实现这个条件查询。

This 链接有一些解释，但没有显示完整的实现

Answer 1

来自documentation，使用 Spring Data MongoDB 支持 MongoDB 聚合框架的典型示例如下所示：

import static org.springframework.data.mongodb.core.aggregation.Aggregation.*;

Aggregation agg = newAggregation(
    pipelineOP1(),
    pipelineOP2(),
    pipelineOPn()
);

AggregationResults<OutputType> results = mongoTemplate.aggregate(agg,
    "INPUT_COLLECTION_NAME", OutputType.class);
List<OutputType> mappedResult = results.getMappedResults();

请注意，如果您将输入类作为第一个参数提供给 newAggregation 方法 MongoTemplate 将派生的名称 此类的输入集合。否则，如果您不指定 输入类，您必须提供输入集合的名称 明确地。如果提供了输入类和输入集合 后者优先。

---

对于您的查询，创建一个实现 AggregationOperation 接口的解决方法，以接收一个 DBObject，它表示具有 $cond 运算符：

public class GroupAggregationOperation implements AggregationOperation {
    private DBObject operation;

    public GroupAggregationOperation (DBObject operation) {
        this.operation = operation;
    }

    @Override
    public DBObject toDBObject(AggregationOperationContext context) {
        return context.getMappedObject(operation);
    }
}

然后将$group 操作实现为聚合管道中的DBObject，与您拥有的相同：

DBObject operation = (DBObject) new BasicDBObject("$group", new BasicDBObject("_id", null))
    .append(
        "Package", new BasicDBObject(
            "$sum", new BasicDBObject(
                "$cond", new Object[]{
                    new BasicDBObject(
                        "$eq", new Object[]{ "$treatmentArms.mechanismOrPkg", "Package"}
                    ),
                    1,
                    0
                }
            )
        )
    );

然后您可以将其用作：

import static org.springframework.data.mongodb.core.aggregation.Aggregation.*;

GroupAggregationOperation groupOp = new GroupAggregationOperation(operation);
Aggregation agg = newAggregation(
    group("iecode").first("treatmentArms").as("treatmentArms"),
    unwind("treatmentArms"),
    groupOp 
);
AggregationResults<Entity> results = mongoTemplate.aggregate(agg, Entity.class); 
List<Entity> entities = results.getMappedResults();