如何在 web api 2 中为 get 方法编写异步 web api？

Question

显示“此异步方法缺少等待”的警告。请建议在我的异步方法中添加等待的位置？

 public async Task<IHttpActionResult> GetEmployeeDetails(string id,string StartDate, string EndDate)
        {
            DateTime sd = Convert.ToDateTime(StartDate);
            DateTime ed = Convert.ToDateTime(EndDate);
            using (EmployeeEntities db = new EmployeeEntities ())
            {
                try
                {
                    return Ok(db.employees.Where(x => x.TimeStamp >= sd && x.TimeStamp <= ed && x.DeviceImei ==id).OrderByDescending(x => x.id).ToListAsync());
                }
                catch (Exception)
                {
                    return BadRequest("Sorry Error Found!!!");
                }
            }
        }

Answer 1

你可以在你使用ToListAsync()的return语句中使用它

return Ok(await db.employees.Where(x => x.TimeStamp >= sd && x.TimeStamp <= ed && x.DeviceImei ==id).OrderByDescending(x => x.id).ToListAsync());