【发布时间】:2020-07-24 02:55:15
【问题描述】:
我编写了一个 Java 程序来解决多线程中的生产者消费者问题。但它不能正常工作。 程序:
public class ConsumerAndProducer {
static int products = 0;
static int capacity = 10;
public static void main(String[] args) {
new Thread(new Producer()).start();
new Thread(new Consumer()).start();
}
static class Consumer implements Runnable{
public void consume() {
synchronized (ConsumerAndProducer.class){
if(products <= 0){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
products--;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Consumer, remain:" + products);
if(products == 9){
notify();
}
}
}
@Override
public void run() {
while(true){
consume();
}
}
}
static class Producer implements Runnable{
public void produce() {
synchronized (ConsumerAndProducer.class){
if(products == capacity){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
products++;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("Producer, remain:" + products);
if(products == 1){
notify();
}
}
}
@Override
public void run() {
while(true){
produce();
}
}
}
还有错误:
Producer, remain:1
Exception in thread "Thread-0" java.lang.IllegalMonitorStateException
at java.lang.Object.notify(Native Method)
at zhousai.ConsumerAndProducer$Producer.produce(ConsumerAndProducer.java:69)
at zhousai.ConsumerAndProducer$Producer.run(ConsumerAndProducer.java:77)
at java.lang.Thread.run(Thread.java:748)
Consumer, remain:0
Exception in thread "Thread-1" java.lang.IllegalMonitorStateException
at java.lang.Object.wait(Native Method)
at java.lang.Object.wait(Object.java:502)
at zhousai.ConsumerAndProducer$Consumer.consume(ConsumerAndProducer.java:22)
at zhousai.ConsumerAndProducer$Consumer.run(ConsumerAndProducer.java:43)
at java.lang.Thread.run(Thread.java:748)
【问题讨论】:
-
永远不要在同步语句或方法中调用 Thread.sleep()。
标签: java multithreading producer-consumer