【发布时间】:2018-12-10 05:44:23
【问题描述】:
当我尝试运行此代码时,我得到的只是一个警告,即 gets() 太危险,无法使用。然后当我运行它时,我会变得空白。我想显示这个:
Ollie 2.9 freshmen
John 3.2 senior
Julie 2.2 freshmen
Joe 1.8 freshmen
Mary 3.8 senior
Sue 3.4 junior
Jane 2.7 senior
Bob 2.8 senior
Fred 3.2 freshmen
Bill 3.3 junior
这是我的代码:
Student *top = NULL; // to point top node of list
Student * temp, *temp1, *temp2; // for traversing list
// Creates the entire linked list from the file.
// Should call readNext and push
// Returns head of the linked list
Student *buildStudentList()
{
Student *p; // will hold the data to be pushed in list
p = readNext();
push(&top, p);
return top; //TODO: Change return
}
//Read a single line from standard input and return a student structure located on the heap
Student *readNext()
{
Student *s = (Student*)malloc(sizeof(Student)); // allocating dynamic memory in heap
printf("Please Enter Student Name, gpa, year :");
gets(s->name);
scanf("%f", &s->gpa);
gets(s->year);
s->next = NULL; // initially make next as NULL
return s; //TODO: Change return
}
//Return a student structure stored on the heap
Student *makeStudent(char *name, float gpa, char *year)
{
Student *s = (Student*)malloc(sizeof(Student));// allocating memory in heap
s->name = name;
s->gpa = gpa;
s->year = year;
s->next = NULL;
return s; //TODO: Change return
}
//insert a new student node at the head of the linked list
void push(Student **list, Student *student)
{
top = *list;
student->next = top; // assign current top node of list to be second node of the list
top = student; // make current node as top node of the list
printf("push successful.\n");
}
//Insert a student node in the desired position on the linked list
void insert(Student *list, Student *s, int position)
{
int i;
top = list;
temp = top;// temp is for traversing the list
for (i = 1; i < position - 1; i++) // loop to reach desired position in the list
{
temp = temp->next;
}
if (temp == NULL)
{
printf("Position does not exist.\n");
}
else
{
s->next = temp->next;
temp->next = s;
}
}
//Displays contents of a single student structure
void display(Student *s) {
printf("NAME:%s\t| GPA:%f\t| YEAR:%s\n", s->name, s->gpa, s->year);
}
//Displays contents of the entire linked list
void displayAll(Student *list)
{
temp = list;
while (temp != NULL)
{
display(temp);
temp = temp->next;
}
}
//Delete all data allocated on the heap before terminating program
void cleanUp(Student *list)
{
temp1 = list; // will point to the top node of list
temp2 = temp1->next; // will point to the second node of the list
while (temp1 != NULL)
{
free(temp1);
temp1 = temp2;
temp2 = temp2->next;
}
printf("Cleanup Successful.\n");
}
//Main function tests your functions.
int main()
{
Student *list, *s;
printf("Program Started ");
//Construct Linked List from Standard Input
list = buildStudentList();
//Insert a new student in desired position
s = makeStudent("Max", 3.0, "senior");
insert(list, s, 1);
//Display entire linked list
displayAll(list);
//Free all heap memory
cleanUp(list);
printf("Program Successful Exit ");
return 0;
//exit(EXIT_SUCCESS);
}
这是我得到的输出:
Program Started
Segmentation fault
我应该尝试使用 fgets() 而不是 gets() 吗?我试图做的输出是不同文件的一部分,这对它有影响吗?
【问题讨论】:
-
这段代码确实很危险。您正在将字符串读入未初始化的指针。
fgets不会帮你解决这个问题。 -
你不应该使用
gets,句号。但你的问题在别处。 -
您在第一条评论中被告知您有未初始化的指针。这才是真正的问题。
-
请不要每隔一行使用换行符。并缩进你的代码。
-
你能展示
Student结构的声明吗?name和year是如何定义的?