在 MongoDb 中使用 addToSet 时保持原始文档的顺序

Question

我阅读了文档，发现 addToSet 不保证顺序。 但是有什么办法可以将订单保留为原始文档。 我的查询是：-

    aggregate([{$match: {
      $or:[{"Name.No":"119"},{"Name.No":"120"}]
    }}, {$project: {
      x:{$objectToArray:"$Results"}
    }},{$unwind: "$x"},{$group: {_id: "$x.k", distinctVals: {$addToSet: "$x.v.TCR"}}}])

样本数据：

{"Name" : {"No." : "119","Time" : "t"},
"Results":{"K1" : {"Counters" : x, "TCR" : [{"Name" : "K11", "Result" : "PASSED"}, 
                                             {"Name" : "K12","Result" : "FAILED"},
                                             {"Name" : "K13","Result" : "PASSED"}]
                    },
            "K2" : {"Counters": y, "TCR" : [{"Name" : "K21","Result" : "PASSED"},              
                                            {"Name" : "K22","Result" : "PASSED"}]
                      
                    }
            
           }
}

} 工作2；

 {"Name" : {"No." : "120","Time" : "t1"},
"Results":{"K1" : {"Counters" : x, "TCR" : [{"Name" : "K11", "Result" : "PASSED"}, 
                                             {"Name" : "K12","Result" : "PASSED"},
                                             {"Name" : "K13","Result" : "FAILED"}]
                    },
            "K3" : {"Counters": y, "TCR" : [{"Name" : "K31","Result" : "PASSED"},              
                                            {"Name" : "K32","Result" : "PASSED"}]
                      
                    }
            
           
}

} 预期；

 {"Name" : {"No." : "119-120","Time" : "lowest(t,t1)"},
"Results":{"K1" : {"Counters" : x, "TCR" : [{"Name" : "K11", "Result" : "PASSED"}, 
                                             {"Name" : "K12","Result" : "PASSED"},
                                             {"Name" : "K13","Result" : "PASSED"}]
                    },
            "K2" : {"Counters": y, "TCR" : [{"Name" : "K21","Result" : "PASSED"},              
                                            {"Name" : "K22","Result" : "PASSED"}]
                      
                    },
             "K3" : {"Counters": y, "TCR" : [{"Name" : "K31","Result" : "PASSED"},              
                                            {"Name" : "K32","Result" : "PASSED"}]
                      
                    }
            
           
}

} 我想保持与原始文档相同的顺序，而且每次文档都会更改，所以我无法根据任何参数进行排序。

Answer 1

• 使用$objectToArray将结果对象转换为数组格式
• $unwind解构Results数组
• $unwind解构Results.v.TCR数组
• $match 过滤PASSED 结果
• $group by Results.k 并获得第一个Name，获得第一个Counters，构造Results.v.TCR 的数组
• $group by null 得到最小值Time，构造No的唯一数组，在键值对中构造Results数组，$reduce迭代TCR的循环并删除重复文档
• $project 显示必填字段，使用 $arrayToObject 将 Results 数组转换为对象，将 No 数组转换为字符串并使用“-”连接

db.collection.aggregate([
  { $addFields: { Results: { $objectToArray: "$Results" } } },
  { $unwind: "$Results" },
  { $unwind: "$Results.v.TCR" },
  { $match: { "Results.v.TCR.Result": "PASSED" } },
  {
    $group: {
      _id: "$Results.k",
      Name: { $first: "$Name" },
      Counters: { $first: "$Results.v.Counters" },
      TCR: { $push: "$Results.v.TCR" }
    }
  },
  {
    $group: {
      _id: null,
      Time: { $min: "$Name.Time" },
      No: { $addToSet: "$Name.No" },
      Results: {
        $push: {
          k: "$_id",
          v: {
            Counters: "$Counters",
            TCR: {
              $reduce: {
                input: "$TCR",
                initialValue: [],
                in: {
                  $cond: [
                    {
                      $in: [
                        {
                          Name: "$$this.Name",
                          Result: "$$this.Result"
                        },
                        "$$value"
                      ]
                    },
                    "$$value",
                    {
                      $concatArrays: [
                        "$$value",
                        [
                          {
                            Name: "$$this.Name",
                            Result: "$$this.Result"
                          }
                        ]
                      ]
                    }
                  ]
                }
              }
            }
          }
        }
      }
    }
  },
  {
    $project: {
      _id: 0,
      Results: { $arrayToObject: "$Results" },
      Name: {
        Time: "$Time",
        No: {
          $reduce: {
            input: "$No",
            initialValue: "",
            in: {
              $concat: [
                "$$value",
                { $cond: [{ $eq: ["$$value", ""]}, "", "-"] },
                "$$this"
              ]
            }
          }
        }
      }
    }
  }
])

Playground

“。” （点）在“不”。字段无效，可能会导致 mongodb 查询操作出现问题，我建议不要使用“。” （点）作为字段名。