Mongoose：如果值存在于对象数组中的数组中，则过滤数据

Question

我有一个使用 Aggregate 的工作 mongoose 查询，我根据对象数组中的值过滤数据，但由于需求变化而遇到麻烦。

这是我的数据在 MongoDB 中的样子（它已经填充了虚拟数据）

{
"_id" : ObjectId("5ef44528af5a1a2a641cd52b"),
"active" : true,
"name" : "CompanyA",
"contacts" : [ 
    {
        "secondary_emails" : [],
        "_id" : ObjectId("5f19727495f4da29403923e3"),
        "email" : "contact@gmail.com",
        "designation" : "VP Cloud & Security",
        "address" : "",
        "name" : "Ron"
    }
],
"services" : [ 
    {
        "active" : true,
        "_id" : ObjectId("5ef44528af5a1a2a641cd52d"),
        "name" : "Company Management",
        "title" : "Company Helpline",
        "description" : "Offering voice, meetings, collaboration and contact center all on one cloud platform.",
        "categories" : [ 
            "SD-WAN", 
            "Security and Compliance"
        ],
        "sub_categories" : [ 
            "Solution"
        ],
    },
    {
      "active" : true,
      "_id" : ObjectId("5ef44528af5a1a2a641cd52c"),
      "name" : "Company HR",
      "title" : "Human Resources",
      "description" : "Offering HR Services to all",
      "categories" : [ 
          "HR", "Company"
      ],
      "sub_categories" : [ 
          "Solution"
      ],
  }
]}

目标：根据用户提供的类别（假设其“SD-WAN”）过滤服务，之前类别是单数，现在是一组值，因为一个服务可以属于多个类别

以前的解决方案 我用于奇异类别值的猫鼬查询如下：

db.Collection("suppliers").aggregate([
  {
    $project: {
      services: {
        $filter: {
          input: "$services",
          as: "services",
          cond: { $eq: ["$$services.category", "SD-WAN" ] },
        },
      },
    },
  },
  { $match: { services: { $exists: true, $not: { $size: 0 } } } },
]);

我在尝试在 $$services.categories 中搜索 SD-WAN 时遇到问题，这是一个值数组。有没有办法更新上述查询以使用 $eq 管道运算符或其他解决方案搜索 services.categories 数组中的值。

预期结果

"_id" : ObjectId("5ef44528af5a1a2a641cd52b"),
"services" : [ 
    {
        "active" : true,
        "_id" : ObjectId("5ef44528af5a1a2a641cd52d"),
        "name" : "Company Management",
        "title" : "Company Helpline",
        "description" : "Offering voice, meetings, collaboration and contact center all on one cloud platform.",
        "categories" : [ 
            "SD-WAN", 
            "Security and Compliance"
        ],
        "sub_categories" : [ 
            "Solution"
        ],
    }
]

如果有人能帮助我解决这个问题，我将不胜感激。如果需要更多信息，请询问。谢谢。

Answer 1

这就是你要找的东西。

[
  {
    $unwind: "$services"
  },
  {
    $match: {
      "services.categories": "SD-WAN"
    }
  },
  {
    $group: {
      _id: "$_id",
      active: {
        $first: "$active"
      },
      name: {
        $first: "$name"
      },
      contacts: {
        $first: "$contacts"
      },
      services: {
        $addToSet: "$services"
      }
    }
  }
]

1. 使用$unwind 来展平数组
2. 使用$match进行过滤
3. 使用$group 将其分组。

我们仅扁平化服务。这就是为什么我使用$addToSet

工作Mongo playground

Answer 2

这是另一种不使用聚合的方法 游乐场链接：https://mongoplayground.net/p/jmLghGBXb7f

db.collection.find({
  "services": {
    $elemMatch: {
      categories: {
        $regex: "SD-WAN",
        $options: "i"
      }
    }
  }
},
{
  "services": {
    $elemMatch: {
      categories: {
        $regex: "SD-WAN",
        $options: "i"
      }
    }
  }
})

输出：

[
  {
    "_id": ObjectId("5ef44528af5a1a2a641cd52b"),
    "services": [
      {
        "_id": ObjectId("5ef44528af5a1a2a641cd52d"),
        "active": true,
        "categories": [
          "SD-WAN",
          "Security and Compliance"
        ],
        "description": "Offering voice, meetings, collaboration and contact center all on one cloud platform.",
        "name": "Company Management",
        "sub_categories": [
          "Solution"
        ],
        "title": "Company Helpline"
      }
    ]
  }
]