我不知道我在 Just BASIC 上运行的这段代码有什么问题答案

【问题标题】：I don't know what's wrong with this code I'm running on Just BASIC我不知道我在 Just BASIC 上运行的这段代码有什么问题
【发布时间】：2013-07-12 09:36:40
【问题描述】：

[Start]
n=INT((RND*10)+1)
PRINT "I have thought of a number."
PRINT "Try to guess it!"
PRINT "Enter your guess."
INPUT g

[Right]
IF g=n THEN GOTO [Finish]
**IF g < n PRINT "Your guess was wrong. Try again. The correct answer was "; n;"." THEN GOTO [Start]
IF g > n PRINT "Your guess was wrong. Try again! The correct answer was "; n;"." THEN GOTO [Start]**

[Finish]
PRINT "Well done! You guessed it."
END

【问题讨论】：

本世纪没用过BASIC，但我觉得你用THEN是不对的。
我还没有得到任何线索，但我很想用这个在线编译器onlinecompiler.net/basic 来解决这个问题。如果我到了任何地方，我会通知你（不过不要屏住呼吸）
这是什么语言？我确信它不是 BASIC，因为有“PRINT”。也许我可以帮助你，如果你能说出它是什么语言。

标签： basic

【解决方案1】：

IF condition THEN positive ELSE negative

但是，这个

IF g > n THEN PRINT "Your guess was wrong. Try again! The correct answer was "; n;"."; GOTO [Start]

不会做你想做的事，因为 IF...THEN...ELSE 语句在打印之后结束，随后的 GOTO 将在任何一种情况下运行。

在大多数 BASIC 中，您可以这样做：

IF g > n THEN 
  PRINT "Your guess was wrong. Try again! The correct answer was "; n;"."; 
ELSE
  GOTO Start
END IF

但我不确定你的口味。

【讨论】：

【解决方案2】：

虽然它可以用更少的 GOTO 来编写，但这也应该有效：

[Start]
n=INT((RND*10)+1)
PRINT "I have thought of a number."
PRINT "Try to guess it!"
PRINT "Enter your guess."
INPUT g

[Right]
IF g=n THEN GOTO [Finish]

PRINT "Your guess was wrong. Try again. The correct answer was "; n;"."     
GOTO [Start]

[Finish]
PRINT "Well done! You guessed it."
END

【讨论】：